Answer:
A-2, B-5, C-1, D-6, E-3, F-4
Step-by-step explanation:
The A would be the function x^3, so it would be the volume of a cube which is #2
B is probably the temperature graph, because it is warmest in the middle of the day and cooler at both ends, so that is #5
C is probably the age of an oak tree because it starts at 0, and grows linearly. #1
E is #3 because it is decreasing and so is the fuel in the tank.
F is the area of a triangle one, because that would be a quadratic function (half of a parabola)#4
D is the car wash, it doesn't start at 0 because the x-axis is the time of day. #6
Answer:
B. The interquartile range is 55
Step-by-step explanation:
the interquartile range is Q3 minus Q1, you would get 15 ,not 55. So B is the answer to your question
For squrae
area=side²
perimiter=4(side)
for circle
area=pir²
circumference=2pir
side=diameter, diameter/2=radius=side/2
find area not covered
that is areasquare-areacircle
areasquare=26²=676 sqauare inches
areaciecle, diameter=side, 26/2=13, area=pi13²=169*3.14=530.66 square inches
areanotcovered=676-530.66=145.34 square inches not coverd
ratio of perimiter to circumferece
perimiter=4*26=104
circumference=2pir=2pi13=26pi=26*3.14=81.64
circumference to perimiter is 81.64/104=0.785
