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Svetach [21]
2 years ago
14

Sheila painted 15 portraits every 25 minutes. At that rate, how long, in

Mathematics
1 answer:
padilas [110]2 years ago
8 0

Answer:

30 minutes

Step-by-step explanation:

15/25=18/x

25/15=x/18

18(25/15)=x

450/15=x

x=30

it will take 30 minutes

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The volume is 472.5in^3.

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4 years ago
In FGH, the measure of H=90°, HF=91 feet, and GH = 50 feet. Find the measure of F to the nearest degree.
Rudik [331]

Given:

The angle of H=90°, HF=91 feet, and GH = 50 feet.

The objective is to find the measure of angle<em> F.</em>

In the given right angled triangle, the side opposite to the requierd angle is called opposite side, and the other smaller side is called adjacent side.

The trigonometry formula which relates with the opposite and adjacent side is,

\tan \theta=\frac{opposite}{adjacent}

Now substitute the value of opposite and adjacent in the above formula to find the value of angle <em>F</em>.

\begin{gathered} \tan \theta=\frac{50}{91} \\ \theta=\tan ^{-1}(0.549) \\ \theta=28.787^0 \\ \theta\approx29^0 \end{gathered}

Hence, the value of angle <em>F</em> is 29 degree.

3 0
1 year ago
Which system of linear inequalities is graphed?
iragen [17]
I am sure that This one would be c
6 0
4 years ago
Read 2 more answers
6. The population of a town is 680 000 correct to the nearest 10 000. Write down
serg [7]

Answer:

a) 675 000

b) 685 000

Step-by-step explanation:

The population of a town is 680 000 correct to the nearest 10 000.

a) To find it lower bound, we level of accuracy by 2 and then subtract from 680 000

The lower bound is:

680 000-5000=675,000

Therefore the least possible population of the town is 675 000

b) We repeat the same process to find the upper bound

680 000+5000=685,000

6 0
4 years ago
Jill and Erica make 4 gallons of lemonade for their lemonade stand. If they charge $2.00 per quart, how much money will they mak
Karo-lina-s [1.5K]

Answer:

They will have 32 dollars

Step-by-step explanation:

4 Gallons are 16qt

Sooo....

Multiply 16*2.00=32.00

7 0
3 years ago
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