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3 years ago

4xsquared 12x 10 is less than or equal to 0 (or what multiplies to get 40 and adds to get 12)

Mathematics

1 answer:

g100num [7]3 years ago

5 0

It either x=5 or x=-2 not sure which on

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What is the value of x

harkovskaia [24]

Answer: x=37.8, you can solve by writing a proportion

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3 years ago

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I need help ASAP ???

kondor19780726 [428]

Answer:

He said he accidentally sent this so I just want everyone who reads this to have a good rest of their day:)

Step-by-step explanation:

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3 years ago

A 15 ft. telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42° angle

Lorico [155]

Answer:

Correct choice is A

Step-by-step explanation:

Consider right triangle ABC formed by the telephone pole (side AB) and ground (side BC). In this triangle AC is the length of the wire, BC is the distance from the base of the pole to the spot where the wire touches the ground and AB=15 ft, ∠ACB=42°.

Then

$\sin 42^{\circ}=\dfrac{AB}{AC}\Rightarrow AC=\dfrac{AB}{\sin 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 22.4\ ft.$
$\tan 42^{\circ}=\dfrac{AB}{BC}\Rightarrow BC=\dfrac{AB}{\tan 42^{\circ}}=\dfrac{15}{\sin 42^{\circ}}\approx 16.7\ ft.$

8 0

3 years ago

28 < 4v <br> solve for v <br> pls help

DedPeter [7]

Answer:

v = 7

Step-by-step explanation:

Divide both sides by 4 to isolate v

28/4 = 4v/4

v = 7

5 0

3 years ago

You are in charge of managing the advertising for a restaurant. You are able to buy up to 62 advertisements a month, and your da

erik [133]

Answer:

Greatest number of newspaper ads = 59

Greatest number of television ads = 23

Step-by-step explanation:

It is given that we should buy at least 5 newspapers for every 3 television ads.

So, after purchasing 3 television ads, we can buy any number of television ads but the number should be greater than 5.

Since, the maximum is 62, we can buy 59 newspaper ads. (Note that we have already bought 3 television ads).

For every 3 television ads, we should buy 5 newspaper ads. So,

For the purchase of 3 television ads, we should buy the minimum of 5 newspaper ads.

For the purchase of 2(3) television ads, we should buy the minimum of 2(5) newspaper ads.

For the purchase of 3(3) television ads, we should buy the minimum of 3(5) newspaper ads.

...

For the purchase of 7(3) = 21 television ads, we should buy the minimum of 7(5) = 35 newspaper ads.

So, totally 21+35 = 56 ads.

For the remaining 6 ads, if we buy 3 television ads, we should buy 5 newspaper ads.

So, we can buy 2 television ads and 4 newspaper ads.

Hence, we can buy the maximum of 21+2 = 23 television ads.

7 0

3 years ago

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