Answer:
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Option C
The distance of a spin of one full rotation is 31.4 feet
<em><u>Solution:</u></em>
Given that,
A circular merry-go-round has a radius of 5 feet
Radius = 5 feet
We have to find the distance of spin for one full rotation
Distance covered in 1 full of rotation is equal to circumference of circle
<em><u>The circumference of circle is given as:</u></em>

Where "r" is the radius

Thus the distance of a spin of one full rotation is 31.4 feet
Answer:
5x^4
Step-by-step explanation:
<u><em>Re-order terms so constants are on the left</em></u>
x^2*x^2*5
5x^2*x^2
<em><u>Combine exponents</u></em>
5x^2*x^2
5x^4
<h2>(PLS GIVE <u><em>
brainliest</em></u>)</h2>
Answer:
Domain {x : x > 1}
Range {y : y ∈ R}
Vertical asymptote x = 0
x-intercept (1, 0)
End behavior consistent
Graph attached down
Step-by-step explanation:
Let us study the equation:
∵ y = log(x)
→ It is a logarithmic function, so no negative values for x
∴ Its domain is {x : x > 1}
∴ Its range is {y : y ∈ R}, where R is the set of the real numbers
→ An asymptote is a line that a curve approaches, but never touches
∵ x can not be zero
∴ It has a vertical asymptote whose equation is x = 0
→ x-intercept means values of x at y = 0, y-intercept means
values of y at x = 0
∵ x can not be zero
∴ There is no y-intercept
∵ y can be zero
∴ The x-intercept is (1, 0)
→ The end behavior of the parent function is consistent.
As x approaches infinity, the y-values slowly get larger,
approaching infinity
∵ y = log(x) is a parent function
∴ The end behavior is consistent
→ The graph is attached down