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Harman [31]
3 years ago
13

Please help me idk this

Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0

Answer:

SA=94

Step-by-step explanation:

SA= 2(4*5) + 2(4*3) + 2(5*3)

SA=2(20) + 2(12) + 2(15)

SA=40 + 24 + 30

SA=94

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How to round 153,394 to the nearest hundred thousand
e-lub [12.9K]
The number next to the one is a five, which tells you that you need to round up. So, when rounding to the nearest hundred thousand, the answer would be 200,000 :) Hope this helped!
8 0
2 years ago
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Pllzlzz answer
rusak2 [61]

Answer:

x ≈ 6

Step-by-step explanation:

The legs of an isosceles triangle are congruent , both 2x - 4 , then

x + 2x - 4 + 2x - 4 = 24 , that is

5x - 8 = 24 ( add 8 to both sides )

5x = 32 ( divide both sides by 5 )

x = 6.4 ≈ 6 ( to the nearest whole number )

8 0
2 years ago
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MakcuM [25]
I believe the answer is C.
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3 years ago
PLEASE HELP ME ILL GIVE YOU POINTS
Elena-2011 [213]

I think its B.) because if u count it all properly u would realize that they would all have to same numbers to match

3 0
3 years ago
Find the indefinite integral. (Note: Solve by the simplest method—not all require integration by parts. Use C for the constant o
umka2103 [35]

Answer:

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2  ln⁡(1+x^2 )+C

Step-by-step explanation:

∫▒〖1st .2nd dx=1st∫▒〖2nd dx〗-∫▒〖(derivative of 1st) dx∫▒〖2nd dx〗〗〗

Let 1st=arctan⁡(x)

And 2nd=1

∫▒〖arctan⁡(x).1 dx=arctan⁡(x) ∫▒〖1 dx〗-∫▒〖(derivative of arctan(x))dx∫▒〖1 dx〗〗〗

As we know that  

derivative of arctan(x)=1/(1+x^2 )

∫▒〖1 dx〗=x

So  

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-∫▒〖(1/(1+x^2 ))dx.x〗…………Eq1

Let’s solve ∫▒(1/(1+x^2 ))dx by substitution now  

Let 1+x^2=u

du=2xdx

Multiply and divide ∫▒〖(1/(1+x^2 ))dx.x〗 by 2 we get

1/2 ∫▒〖(2/(1+x^2 ))dx.x〗=1/2 ∫▒(2xdx/u)  

1/2 ∫▒(2xdx/u) =1/2 ∫▒(du/u)  

1/2 ∫▒(2xdx/u) =1/2  ln⁡(u)+C

1/2 ∫▒(2xdx/u) =1/2  ln⁡(1+x^2 )+C

Putting values in Eq1 we get

∫▒〖arctan⁡(x).1 dx=arctan⁡(x).x〗-1/2  ln⁡(1+x^2 )+C  (required soultion)

3 0
3 years ago
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