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Lesechka [4]
3 years ago
12

The stopping distance of a car is directly proportional to the square of the speed of the car. If a car traveling 50 miles per h

our has a stopping distance of 170 feet, find the stopping distance of a car that is traveling 70 miles per hour
Mathematics
1 answer:
snow_tiger [21]3 years ago
6 0
70 / 50 = 1.4
1.4 * 1.4 = 1.96
So, the stopping distance increases by a factor of 1.96
170 feet * 1.96 = 333.20 feet


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Pls help me with my math
natka813 [3]

Answer:

d.

Step-by-step explanation:

Left line is defined when x < 1 (x is less than 1). The point is not full and that means that x = 1 is not included.

Right line is defined when x is greater or equal to one x ≥ 1.

Options that have x < 1 and x ≥ 1 are b and d, so the answer is one of those.

Equations of the lines are in slope-intercept form y = mx + b, where m is slope and b is y-intercept.

Right line has steeper slope than left line, so the slope of right line will have bigger absolute value. That is the case with option d. (Left line has slope -1 and right one has slope -2, absolute value of right slope is bigger.)

You could also check with y-intercepts. Left line has y-intercept at y = 2 and left line is defined when x < 1. Only option d meets these conditions.

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Answer with Step-by-step explanation:

We are given that

f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.

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Substitute x=2-h

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\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}

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Substitute

x=2+h

\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}

=\frac{2}{4}=\frac{1}{2}

LHL=RHL=\frac{1}{2}

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LHL=RHL\neq f(2)

Hence, function is discontinuous at x=2

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