All categories

2 years ago

Helpppppppppppppppppppppppppppp

Mathematics

2 answers:

Mamont248 [21]2 years ago

8 0

Answer:

1 avocado costs $0.50 (4 ÷ 8)

16 avocados cost $8 (0.5 × 16)

20 avocados cost $10 (0.5 × 20)

9 avocados cost $4.50 (0.5 × 9)

Hope this helps!

Furkat [3]2 years ago

3 0

Answer:

1 avocado= 50 cents 16 avocados is 8 dollars 20 avocados are 10 dollars and 9 avocados is 4.50

You might be interested in

.933333333 repeative as a fraction

Tanya [424]

Well if it is a number like .933333333 you will have to round it, So now it is .93 and .93 in a fraction is 93/100

7 0

2 years ago

please please out of certain people of all locality 50% speak Nepali language 55% speak English language and 5% speak not if 40

RSB [31]

The given pics are your answers... Thank you

8 0

2 years ago

Recent census data indicated that 14.2% of adults between the ages of 25 and 34 live with their parents. A random sample of 125

kicyunya [14]

Answer:

The probability is $P(14 < X < 20 ) = 0.5354$

Step-by-step explanation:

From the question we are told that

The proportion that live with their parents is $\r p = 0.142$

The sample size is n = 125

Given that there are two possible outcomes and that this outcomes are independent of each other then we can say the Recent census data follows a Binomial distribution

i.e

$X \ \~ \ B( \mu , \sigma )$

Now the mean is evaluated as

$\mu = n * \r p$

$\mu = 125 * 0.142$

$\mu = 17.75$

Generally the proportion that are not staying with parents is

$\r q = 1 - \r p$

= > $\r q = 0.858$

The standard deviation is mathematically evaluated as

$\sigma = \sqrt{n * \r p * \r q }$

$\sigma = \sqrt{ 125 * 0.142 * 0.858 }$

$\sigma = 3.90$

Given the n is large then we can use normal approximation to evaluate the probability as follows

$P(14 < X < 20 ) = P( \frac{ 14 - 17.75}{3.90}$

Now applying continuity correction

$P(14 < X < 20 ) = P( \frac{ 13.5 - 17.75}{3.90} < \frac{ X - \mu }{\sigma } < \frac{ 19.5 - 17.75}{3.90} )$

Generally

$\frac{ X - \mu }{\sigma } = Z ( The \ standardized \ value \ of X )$

$P(14 < X < 20 ) = P( \frac{ 13.5 - 17.75}{3.90} < Z< \frac{ 19.5 - 17.75}{3.90} )$

$P(14 < X < 20 ) = P( -1.0897 < Z< 0.449 } )$

$P(14 < X < 20 ) = P( Z< 0.449 ) - P(Z < -1.0897)$

So for the z - table

$P( Z< 0.449 ) = 0.67328$

$P(Z < -1.0897) = 0.13792$

$P(14 < X < 20 ) = 0.67328 - 0.13792$

$P(14 < X < 20 ) = 0.5354$

6 0

3 years ago

How to find perimeter of ceiling

KatRina [158]

Answer:

add up the lengths of all the sides of the ceiling,is there a diagram that comes with this or something?

Step-by-step explanation:

6 0

3 years ago

A warehouse employs 21 workers on first shift, 15 workers on second shift, and 13 workers on third shift. Eight workers are ch

Crank

Answer: Our required probability is 0.11.

Step-by-step explanation:

Since we have given that

Number of workers in first shift = 21

Number of workers in second shift = 15

Number of workers in third shift = 13

We need to find the probability of choosing exactly two second shift workers and two third shift workers.

So, it becomes,

$\dfrac{^{15}C_2\times ^{13}C_2\times ^{21}C_4}{^{49}C_8}\\\\=0.11$

Hence, our required probability is 0.11.

3 0

3 years ago