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3 years ago

Helpppppppppppppppppppppppppppp

Mathematics

2 answers:

Mamont248 [21]3 years ago

8 0

Answer:

1 avocado costs $0.50 (4 ÷ 8)

16 avocados cost $8 (0.5 × 16)

20 avocados cost $10 (0.5 × 20)

9 avocados cost $4.50 (0.5 × 9)

Hope this helps!

Furkat [3]3 years ago

3 0

Answer:

1 avocado= 50 cents 16 avocados is 8 dollars 20 avocados are 10 dollars and 9 avocados is 4.50

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A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

The final curse load of the local gym instructor is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

The final course load is this:

High-‐impact aerobics = 1

Low-‐impact aerobics = 4

Jazzercise = 1

Step exercise = 2

7 0

3 years ago

Add. (-x^3+26x^2-7-13)+(6x^4-x^3+8x+27) express the answer in standard form.

Alex777 [14]

$(-x^3+26x^2-7-13)+(6x^4-x^3+8x+27)\\\\=-x^3+26x^2-7-13+6x^4-x^3+8x+27\\\\=6x^4+(-x^3-x^3)+26x^2+8x+(27-7-13)\\\\=\boxed{6x^4-2x^3+26x^2+8x+7}$

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3 years ago

Init. Cantian Sinaniiieeintroduction

tatuchka [14]

Answer:

The independent variable is the amount of miles walked, and the dependent is the total from home.

Step-by-step explanation:

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3 years ago

A rectangle sand box has a length of 5 and 1/3 feet and a width of 3 and 3/4 feet. What is the perimeter?

Varvara68 [4.7K]

Answer:

Perimeter of rectangle = ⇒ $18\frac{1}{6}$ feet

Step-by-step explanation:

Given:

Length of a rectangular sand box = $5\frac{1}{3}\ feet$

Width of the box = $3\frac{3}{4}\ feet$

Perimeter of a rectangle = $2(l+w)$

where $l$ represents length of rectangle and $w$ represents width of the rectangle.

Substituting values given for length and width.

Perimeter of sand box = $2(5\frac{1}{3}+3\frac{3}{4})\ feet$

Simplifying by adding fractions:

⇒ $2(5+3+\frac{1}{3}+\frac{3}{4})\ feet$ (Adding whole numbers and fractions separately)

⇒ $2(8+\frac{1}{3}+\frac{3}{4})$ feet

Whole number 8 can be written as $\frac{8}{1}$

⇒ $2(\frac{8}{1}+\frac{1}{3}+\frac{3}{4})$ feet

To add fractions we take LCD for the denominators 3,4,1.

LCD for 3 and 4 = 12 as its the least common multiple of 3,4,1.

Making denominators =12 by multiplying numerator an denominator with the corresponding numbers

⇒ $2(\frac{8\times 12}{1\times 12}+\frac{1\times 4}{3\times 4}+\frac{3\times 3}{4\times 3})$ feet

⇒ $2(\frac{96}{12}+\frac{4}{12}+\frac{9}{12})$ feet

Then we simply add numerators.

⇒ $2(\frac{96+4+9}{12})$ feet

⇒ $2(\frac{109}{12})$ feet

⇒ $2\times \frac{109}{12}$ feet

⇒ $\frac{218}{12}$ feet

Writing fraction as a mixed number by dividing 218 by 12 and writing quotient as whole number and remainder as numerator with divisor as denominator.

⇒ $18\frac{2}{12}$ feet