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Nikolay [14]
2 years ago
13

Lines l and m are parallel. Find the value of x. enter just the number

Mathematics
1 answer:
faltersainse [42]2 years ago
6 0

Answer:

its x

Step-by-step explanation:

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Find the geometric mean of 5 & 8. Write the exact answer (do NOT round)
yuradex [85]
The geometric mean is defined as the nth root of the product of n numbers.
This means, you multiply all the numbers together
5×8=40
And then you take the nth root of that number. In this case, it's the square root, but if there were more numbers, like three or four, it would be the cube and fourth root, respectively.
√40 = 6.32455532
So, the geometric mean of 5 and 8 is 6.32455532
3 0
3 years ago
What is the equation of the line that passes through the point (-2, 0) and has
garik1379 [7]

Answer:

y = 2x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 2 , then

y = 2x + c ← is the partial equation

To find c substitute (- 2, 0 ) into the partial equation

0 = - 4 + c ⇒ c = 0 + 4 = 4

y = 2x + 4 ← equation of line

8 0
3 years ago
Which is the graph of the function f(x) =1/2x^2-6
Dmitry_Shevchenko [17]
Well it is gonna be compressed inward and down 6 post the graph
8 0
4 years ago
Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.
Firdavs [7]

Step-by-step explanation:

The given expression is :

(\sqrt[3]{128} )^x

We need to solve the above expression.

According to one of the law of indices,  

(\sqrt[a]{m} )^b=(\sqrt{m})^{b/a}

Using above property,

(\sqrt[3]{128} )^x=(128)^{x/3}\\\\=(64\times 2)^{x/3}\\\\=4(2)^{x/3}\ (\because\ \sqrt{64}=4) \\\\=4(\sqrt[3]{2})^x\\\\=4(2^{1/3})^x

Hence, this is the required solution.

3 0
3 years ago
You have a 5" by 7" photo that you would like to have enlarged to fit an 8" by 10" frame. Would the two photographs be similar?
harkovskaia [24]

5/8 = 0.625

7/10 = 0.7

 the 2 ratios are different so it would not be similar

8 0
3 years ago
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