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3 years ago

Which criterion, if any, could prove the triangles are congruent?

Mathematics

1 answer:

Oksi-84 [34.3K]3 years ago

4 0

Answer:

ASA stands for "angle, side, angle" and means that we have two triangles where we know two angles and the included side are equal.

So A

Explanation: If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent

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Compare the scores: a score of 75 on a test with a mean of 65 and a standard deviation of 8 and a score of 75 on a test with a m

LiRa [457]

Answer:

The Zscore for both test is the same

Step-by-step explanation:

Given that :

TEST 1:

score (x) = 75

Mean (m) = 65

Standard deviation (s) = 8

TEST 2:

score (x) = 75

Mean (m) = 70

Standard deviation (s) = 4

USING the relation to obtain the standardized score :

Zscore = (x - m) / s

TEST 1:

Zscore = (75 - 65) / 8

Zscore = 10/8

Zscore = 1.25

TEST 2:

Zscore = (75 - 70) / 4

Zscore = 5/4

Zscore = 1.25

The standardized score for both test is the same.

7 0

3 years ago

Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3

Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

$\frac{dV}{dt} = -kA$

Using Euler's method

$\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i} \\$

Where initial droplet volume is:

$V(0) = \frac{4pi}{3} * r(0)^3 = \frac{4pi}{3} * 2.5^3 = 65.45 mm^3$

Hence, the iterative solution will be as next:

i = 1, ti = 0, Vi = 65.45

$V'_{i} = -k *4pi*(\frac{3*65.45}{4pi})^(2/3) = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88$

i = 2, ti = 0.5, Vi = 63.88

$V'_{i} = -k *4pi*(\frac{3*63.88}{4pi})^(2/3) = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33$

i = 3, ti = 1, Vi = 62.33

$V'_{i} = -k *4pi*(\frac{3*62.33}{4pi})^(2/3) = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813$

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

$r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\$

The average change of droplet radius with time is:

Δr/Δt = $\frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min$

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

5 0

3 years ago

How do you find an exponential growth model

ipn [44]

Answer:

When the line of the graph is going up

Step-by-step explanation:

When the line is going down that means its a exponential decay :)

5 0

3 years ago

An electrical rm manufactures light bulbs that have a life span that is approximately normally distributed. The population stand

stira [4]

Answer:

The 't' test statistic = 1.46 < 1.69

The test of hypothesis is H 0 :μ = 800 is accepted

A sample of 30 bulbs are found came from average µ= 800

Step-by-step explanation:

Step 1:-

Given population of mean μ = 800

given size of small sample n =30

sample standard deviation 'S' = 45

Mean value of the sample χ = 788

Null hypothesis $H_{0} =$ µ =800

alternative hypothesis $H_{1} =$ µ ≠ 800

Step 2:-

The 't' test statistic t = $\frac{x-μ}{\frac{sig}{\sqrt{n} } }$

$t = \frac{788-800}{\frac{45}{\sqrt{30} } }$

t = $\frac{12}{8.215}$ = 1.4607

Step 3:-

The degrees of freedom γ = n-1 = 30-1 =29

From "t" value from table at 0.05 level of significance ( t = 1.69)

The calculated value t = 1.4607 < 1.69

Therefore The null hypothesis H_{0} ' is accepted.

conclusion:-

A sample of 30 bulbs are came found from average µ= 800

7 0

4 years ago

Keith’s dad is 44 years old if this is 4 years less than three times Keith’s age how old is Keith

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

3 0

4 years ago

Read 2 more answers