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WINSTONCH [101]
2 years ago
11

Can someone help? It’s about 2 column proofs

Mathematics
1 answer:
Gwar [14]2 years ago
4 0

Step-by-step explanation:

1. AB = BC (B is the midpoint of AC)

2. DE = EF (E is the midpoint of DF)

3. EB is common

4. ∠ABE = ∠CBE; ∠BED = ∠BEF (EB⊥AC, EB⊥DF)

5. ΔDEB ≅ ΔFEB (RHS)

6. DB = FB (corresponding ∠s of ≅ Δs)

7. ∠EFB = ∠CBF; ∠EDB = ∠ABD (alternate interior angles, AC║DF)

8. ΔABD ≅ ΔCBF (SAS)

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Which of the following pairs of organisms compete with each other for food?
erastovalidia [21]
The answer would be D. Mice and Rabbits. Hope it helps! :)
8 0
3 years ago
Read 2 more answers
The new ointment was applied to four locations, and a control was applied to the other four. How many different choices were the
lubasha [3.4K]

Answer:

there are 70 possible choices for the four locations to apply the new ointment

Step-by-step explanation:

Since we have a total of 8 locations ( 4 to the new ointment and 4 to the control) ,  each one can be chosen and since the order of the locations that are chosen for the new ointment is not relevant  , then we know that the number of choices is given by the number of combinations of 4 elements in 8

number of combinations = 8 possible locations to the first ointment * 7 possible locations to the second ( since the first one was already located) * 6 to the third * 5 locations for the fourth / number of times the same combination is repeated ( the same locations but in different positions) = 8*7*6*5 / (4 possible positions for the first ointment* 3 possible positions to the second ointment (since the first one was already located * 2 possible positions of the third * 1 possible position of the fourth)

therefore

number of combinations = 8*7*6*5/(4*3*2*1 ) = 8!/((8-4)!*4!) = 70 possible combinations

thus there are 70 possible choices for the four locations to apply the new ointment

6 0
3 years ago
Guys answer this one only one more question left
Karo-lina-s [1.5K]

Answer:

336

Step-by-step explanation:

i hope i got it right

6 0
3 years ago
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Pls help im not smart enough ;-;
evablogger [386]
PART1:

First Combination:
Pizza ($7) + Chicken Strips ($6) + Biscuits ($3) + Grapes ($4) = $20

Second Combination:
Dog Food ($13) + Bread ($3) + Crackers ($2) + Broccoli ($2) = $20

Third Combination:
Shampoo ($4) + Tissues ($3) + Pizza ($7) + Eggs ($3) + Biscuits ($3) = $20


PART 2:

First Combination:
$7.20 + $5.70 + $2.90 + $3.70 = $19.60
No, I wouldn’t have gone over the limit

Second Combination:
$13.40 + $3.50 + $2.00 + $1.90 = $20.80
Yes, I would have gone over the limit

Third Combination:
$3.50 + $2.60 + $7.20 + $2.50 + $2.90 = $18.70
No, I wouldn’t have gone over the limit

Hope this helps!!



7 0
3 years ago
adrian began riding his scooter at 7:00am. He stopped riding it at 8:10am. How long did adrian ride his scooter for?​
Alenkinab [10]

Answer:

Adrian rode his scooter for a total of 70 minutes, or an hour and ten minutes.

Step-by-step explanation:

There are 60 minutes in an hour, so if Adrian started riding his scooter at 7:00AM, to get to 8:10AM he needs to add 70.  Again, since there are 60 minutes in an hour, 70 minutes converts to one hour and 10 minutes.  Adrian rode his scooter for 70 minutes, or an hour and ten minutes.

7:00 + :70 = 8:10

8 0
2 years ago
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