Step-by-step explanation:
1. AB = BC (B is the midpoint of AC)
2. DE = EF (E is the midpoint of DF)
3. EB is common
4. ∠ABE = ∠CBE; ∠BED = ∠BEF (EB⊥AC, EB⊥DF)
5. ΔDEB ≅ ΔFEB (RHS)
6. DB = FB (corresponding ∠s of ≅ Δs)
7. ∠EFB = ∠CBF; ∠EDB = ∠ABD (alternate interior angles, AC║DF)
8. ΔABD ≅ ΔCBF (SAS)
perimeter = 2L+2w
from the problem L = 1/5w-2
so perimeter = 2(1/5w-2) +2w
= 2/5w-4 +2w
=12/5w-4
without seeing your choices it should be similar to this
Answer:
where is the graph
Answer: See below
