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Kryger [21]
3 years ago
5

In a nursery class of 18 pupils, the average is

Mathematics
2 answers:
melamori03 [73]3 years ago
8 0

Answer:

The sum of the age of pupils is 81

Step-by-step explanation:

Let sum of age of 18pupils = x

Average ages = 4.5

Average = total/no. of pupil

4.5 = x/18

x = 81

dimaraw [331]3 years ago
6 0

Answer:

The sum of the age of pupils is 81

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Simplify 2[(9 - 5)^5 / 8]
Alenkinab [10]
2[(9 - 5)^5/8] = 2[4^5/8] = 2[1024/8] = 2[128] = 256
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3 years ago
Water is being drained at a constant rate from a tank.
saw5 [17]

Answer:

Step-by-step explanation:

1000 gallons - 940 = 60 then divide by the time which gets us 60/10=6

Now we can use this answer to help find out the amount remaining in the tank.

5 minutes = 5x6=30; 1000-30= 970 gallons

20 minutes= 20x6=120; 1000-120= 880 gallons

30 minutes=30x6=180; 1000-180= 820 gallons

27 minutes=27x6=162; 1000-162= 838 gallons

X minutes = 1000-6x

Rate of flow is 6 gallons per minute.

Hope this helps!

3 0
3 years ago
A certain electronics manufacturer found that the average cost C to produce x DVD/Blu- ray players can be found using the equati
Marina CMI [18]

Answer:

Minimum average cost = 743.75

Number of dvds to achieve the cost = 62.5

Step-by-step explanation:

Given the cost equation

C = 0.04x² − 5x + 900

To Obtian the minimum average cost ;

Find dc/dx = 0

Diffentiate cost, c it ith respect to x

dc/dx = 2(0.04x) - 5

dc/dx = 0.08x - 5 = 0

0.08x = 5

x = 5 / 0.08

x = 62.5

Substitute the value of x into C to obtain the minimum average cost

C = 0.04(62.5)² - 5(62.5) + 900

C = 743.75

6 0
3 years ago
Write two decimals that are equivalent to 0.9
Maurinko [17]

0.90 and I think .9 is another I'm not sure but I tried

6 0
3 years ago
Read 2 more answers
find the value of x of given figure and solve this question step by step plzz help question number D​​
Alinara [238K]

Answer:

x=15 cm

Step-by-step explanation:

The two triangles in the diagram are:

ABC and BDC

First we have to find the third side (hypotenuse) of BDC so that we can use it to find the value of x.

Hypotenuse is the largest side of a triangle which is usually in front of the right angle.

So in BDC

Base = BD =10cm\\Hypotenuse = BC = ?\\Perpendicular = CD = 2\sqrt{11}cm

Applying Pythagoras theorem:

(Hypotenuse)^2  = (Base)^2 + (Perpendicular)^2\\BC^2 = BD^2 + CD^2\\BC^2 = (10)^2 + (2\sqrt{11})^2\\BC^2 = 100+(2^2 * 11)\\BC^2 = 100+(4*11)\\BC^2 = 100+44\\BC^2 = 144\\\sqrt{BC^2} = \sqrt{144}\\BC = 12cm

Solving for triangle ABC

Base = BC = 12 cm\\Perpendicular = AB = 9 cm\\Hypotenuse = AC = x\\

Applying Pythagoras theorem

AC^2 = BC^2+AB^2\\x^2 = (12)^2 + (9)^2\\x^2 = 144+81\\x^2 = 225\\\sqrt{x^2} = \sqrt{225}\\x = 15cm

Hence,

x=15 cm

8 0
3 years ago
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