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Kryger [21]
3 years ago
5

In a nursery class of 18 pupils, the average is

Mathematics
2 answers:
melamori03 [73]3 years ago
8 0

Answer:

The sum of the age of pupils is 81

Step-by-step explanation:

Let sum of age of 18pupils = x

Average ages = 4.5

Average = total/no. of pupil

4.5 = x/18

x = 81

dimaraw [331]3 years ago
6 0

Answer:

The sum of the age of pupils is 81

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Leo the Rabbit
Alla [95]

Answer:

2?

Step-by-step explanation: because he can hop them one step at a time or two steps at a time

3 0
3 years ago
5. 3x + 5y + 5z =1<br> x - 2y = 5<br> 2x + 4y = 11
lilavasa [31]

Answer:

see explanation

Step-by-step explanation:

Given the 3 equations

3x + 5y + 5z = 1 → (1)

x - 2y = 5 → (2)

2x + 4y = 11 → (3)

Use (2) and (3) to solve for x and y

Multiply (2) by 2

2x - 4y = 10 → (4)

Add (3) and (4) term by term

4x = 21 ( divide both sides by 4 )

x = \frac{21}{4\\}

Substitute this value of x into (3)

2 × \frac{21}{4\\} + 4y = 11

\frac{21}{2\\} + 4y = 11 ( subtract \frac{21}{2\\} from both sides )

4y = \frac{1}{2} ( divide both sides by 4 )

y = \frac{1}{8\\}

Substitute the values of x and y into (1) and solve for z

3 × \frac{21}{4\\} + 5 × \frac{1}{8\\} + 5z = 1

\frac{63}{4} + \frac{5}{8} + 5z = 1

\frac{131}{8} + 5z = 1 ( subtract \frac{131}{8} from both sides )

5z = - \frac{123}{8} ( divide both sides by 5 )

z = - \frac{123}{40}

Solution is

x = \frac{21}{4\\}, y = \frac{1}{8\\}, z = - \frac{123}{40}

3 0
3 years ago
Wondering if anyone could help?
aleksklad [387]

Answer:

error

Step-by-step explanation:

4 0
3 years ago
Find an approximate equation y=ab^x with the coordinates (0, 4) (3, 95)
bogdanovich [222]
We have y=ab^{x}

Plug in (0, 4):
4=ab^{0}⇒4=a
So we now have a

Plug in (3, 95):
95=4b^{3}
⇒b^{3}=\frac{95}{4}
⇒b=\sqrt[3]{\frac{95}{4}}
which is approximately 2.874

So we get
y=4(\sqrt[3]{\frac{95}{4}})^{x}
or, in decimal form,
y=4*2.874^{x}
7 0
3 years ago
Help me with this plz
djyliett [7]
Ok what do u need help with?

7 0
3 years ago
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