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Ilya [14]
2 years ago
9

A certain electronics manufacturer found that the average cost C to produce x DVD/Blu- ray players can be found using the equati

on C = 0.04 x 2 − 5 x + 900 . What is the minimum average cost per machine and how many DVD/Blu-ray players should be built in order to acheive that minimum?
The minimum average cost is ?
The number of DVD/Blu-ray players that should be build to acheive the minimum is?
Mathematics
1 answer:
Marina CMI [18]2 years ago
6 0

Answer:

Minimum average cost = 743.75

Number of dvds to achieve the cost = 62.5

Step-by-step explanation:

Given the cost equation

C = 0.04x² − 5x + 900

To Obtian the minimum average cost ;

Find dc/dx = 0

Diffentiate cost, c it ith respect to x

dc/dx = 2(0.04x) - 5

dc/dx = 0.08x - 5 = 0

0.08x = 5

x = 5 / 0.08

x = 62.5

Substitute the value of x into C to obtain the minimum average cost

C = 0.04(62.5)² - 5(62.5) + 900

C = 743.75

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Answer:

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3 years ago
Claire is going to an amusement park. The price of admission into the park is $30, and once she is inside the park, she will hav
nydimaria [60]

Answer:

1. $66

2. 30 + 4r

Step-by-step explanation:

Let

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Price of every ride in the park=$4

Number of rides =x

Total cost of going to the park= 30+4x

1. How much money would Claire have to pay in total if she goes on 9 rides

Total cost of going to the park= 30+4x

When x=9

=30+4x

= 30 + 4(9)

=30 + 36

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2. How much would she have to pay if she goes on r rides?

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4 0
3 years ago
Read 2 more answers
40 POINTS AND BRAINLIEST
ladessa [460]

Answer:

120

Step-by-step explanation:

As x goes from 1 to 2, y increases by 4 from 4 to 8

As x goes from 2 to 3, y increases by 4 from 8 to 12

We increase by 4 each time

The formula for an arithmetic sequence is

an = a1+d(n-1)

where a1 is the first term which is 4

d is the common difference or the number we add each time which is 4

n is the term we are looking for which is 30

a30 = 4 +4 (30-1)

a30 = 4+4(29)

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5 0
3 years ago
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Help me out here guys
kvasek [131]
D.

f(x) can be written as (x+2)(x-2)(x-1)
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similarly, k(x) can be written as
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3 0
2 years ago
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