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Sholpan [36]
3 years ago
13

Quickly answer number 10 text only no fonts (100 points) mark brainliest

Mathematics
2 answers:
AfilCa [17]3 years ago
8 0

Answer:

Hello again the square root of 625 is 25

FrozenT [24]3 years ago
7 0

25

have a great day! :3

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Step-by-step explanation:

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Jason formed two-digit numbers using the rules.
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a) 5 is the answer

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How do yo slove the problem
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4) In triangle, angle opposite to perpendicular is 90-60 = 30
So, tan Ф = P/B
tan 30 = a / 6
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a = 6/√3
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Solve(100 points to right answer)If you get it wrong or type random stuff you will be reported
anygoal [31]

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24 ft

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The Pew Research Center reported that 73% of Americans who own a cell phone also use text messaging. In a recent local survey, 1
AnnZ [28]

Answer:

z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433  

Now we can find the p value. Since we have a bilateral test the p value would be:  

p_v =2*P(z>1.433)=0.152  

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

Step-by-step explanation:

Information provided

n=200 represent the sample size slected

X=155 represent the cell phone owners used text messaging

\hat p=\frac{155}{200}=0.775 estimated proportion of cell phone owners used text messaging

p_o=0.73 is the value to verify

\alpha=0.1 represent the significance level

We need to conduct a z test for a proportion

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true proportion of cell phone owners used text messaging is different from 0.73 so then the system of hypothesis are:

Null hypothesis:p=0.73  

Alternative hypothesis:p \neq 0.73  

The statistic to check this hypothesis is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the data given we got:

z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433  

Now we can find the p value. Since we have a bilateral test the p value would be:  

p_v =2*P(z>1.433)=0.152  

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

6 0
3 years ago
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