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MrMuchimi
2 years ago
9

What is 7 minus 8 over 3.

Mathematics
2 answers:
LenKa [72]2 years ago
4 0

Answer:

6.625

Step-by-step explanation:

This is the answer because of calculator

tigry1 [53]2 years ago
3 0

Answer:

4.33333333333

the answer is

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What is the yield on a corporate bond with a $1000
White raven [17]

The yield on the corporate bond of a face value of $1000 is 7.77%.

What is the percentage discount?

The percentage discount is the discount given on a product as compared to the given discount on 100 rupees.

Given, the face value of the bond is $1000.

Discounted price of the bond is $900.

Therefore, the fixed interest on the bond for that period will be

= $1000 × 7/100 = $70.

Now, the yield on that corporate  bond = 70 × 100/900 % = 7.77% .

Hence, the yield on the corporate bond of a face value of $1000 is 7.77%.

Learn more about percentage discount here:

brainly.com/question/26178186

#SPJ4

5 0
1 year ago
A family of 2 adults and 1 child plans to spend the day at the baytown zoo . how much does administration for the family cost ex
hodyreva [135]
15.75+15.75=31.50 you add the two 15.75's because there are two adults then you add the amount of the admission for the adults and the kid 31.50+8.25 and you get $39.75
3 0
3 years ago
let t : r2 →r2 be the linear transformation that reflects vectors over the y−axis. a) geometrically (that is without computing a
tangare [24]

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

See the figure for the graph:

(a) for any (x, y) ∈ R² the reflection of (x, y) over the y - axis is ( -x, y )

∴ x → -x hence '-1' is the eigen value.

∴ y → y hence '1' is the eigen value.

also, ( 1, 0 ) → -1 ( 1, 0 ) so ( 1, 0 ) is the eigen vector for '-1'.

( 0, 1 ) → 1 ( 0, 1 ) so ( 0, 1 ) is the eigen vector for '1'.

(b) ∵ T(x, y) = (-x, y)

T(x) = -x = (-1)(x) + 0(y)

T(y) =  y = 0(x) + 1(y)

Matrix Representation of T = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]

now, eigen value of 'T'

T - kI =  \left[\begin{array}{cc}-1-k&0\\0&1-k\end{array}\right]

after solving the determinant,

we get two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Hence,

(a) ( 1, 0 ) is the eigen vector for '-1' and ( 0, 1 ) is the eigen vector for '1'.

(b)  two eigen values of 'k' = 1, -1

for k = 1, eigen vector is \left[\begin{array}{c}0\\1\end{array}\right]

for k = -1 eigen vector is \left[\begin{array}{c}1\\0\end{array}\right]

Learn more about " Matrix and Eigen Values, Vector " from here: brainly.com/question/13050052

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6 0
1 year ago
Twice the sum of a number and negative two is sixteen. find the number
dexar [7]
It would be 9 because 2x9=18. Then 18+-2=16.
5 0
3 years ago
Read 2 more answers
Use the Factor Theorem to determine whether x + 1 is a factor of P(x) = 2x³+4x²–2x−8.
Harman [31]

Answer: 2x^2+2x-4-\frac{4}{x+1}

Not a factor because there is a remainder.

Step-by-step explanation:

Let's use synthetic division to solve this..

-1  ║ 2 | 4 | -2 | -8

   ║    | -2| -2 |  4

   ║ 2 | 2|  -4 |  -4

2x^2+2x-4-\frac{4}{x+1}

PS: if anyone knows a better way to do a synthetic division chart please let me know.

5 0
1 year ago
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