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3 years ago

What is 18% of 700? Enter your answer in the box.

Mathematics

2 answers:

ella [17]3 years ago

4 0

18% of 700 is 126 .18x700=126

frosja888 [35]3 years ago

4 0

Answer:

126

Step-by-step explanation:

i took the test its 126 if u need me to explain how i got it ask

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PLEASE HELP!! What is the slope of the line on the graph?

sammy [17]

Answer:

Step-by-step explanation:

Slope formula is the difference of the y values divided by the difference of x values. Choose to points. I chose (-2,-1) and (0,3). 3-(-1) is equal to 4. 0-(-2) is equal to 2. 4 divided by 2 is two.

5 0

3 years ago

In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the

earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

A = video components need repair within 1 year

B = electronic components need repair within 1 year

C = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events A, B and C are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

$=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278$

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

$=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277$

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

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3 years ago

You are considering developing a regression equation relating a dependent variable to two independent variables. One of the vari

lys-0071 [83]

Answer:

Step-by-step explanation:

a. How many dummy variables are needed to represent the categorical variable?

We need 1 less dummy variable than outcomes for the categorical variable.

categorical variable has 2 outcomes

So, we need 2-1 = 1 dummy variable.

Answer: 1

Note: If our categorical variable had 5 outcomes, we would need 5-1 = 4 dummy variables.

b. Write the multiple regression equation relating the dependent variable to the independent variables.

Note: Depending your your professor, this can be written one of the following ways...

yhat = a + b1 x1 + bx2

yhat = b0 + b1 x1 + b2 x2

yhat = beta0hat + beta1hat x1 + betahat2 x2

where x1 is the ratio variable

and x2 is the dummy variable

c. Interpret the meaning of the coefficients in the regression equation.

b0 = the predicted value of y when x1 and x2 both equal 0.

b1 = the change in y when x1 increases by 1 unit holding x2 constant.

b2 = the predicted difference in y between the two possible outcomes of the categorical variable holding x1 constant.

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4 years ago

A parking lot contains 100 cars , k of which happen to be lemons. we select m of these cars

Sunny_sXe [5.5K]

Given that a parking lot contains 100 cars, k of which happen to be lemons.

This is a conditional probability question.

Let event A be that a car is tested and event B be that a car is lemon.

The probability that a car is lemon is given by $\frac{k}{100}$

The probability that a car is tested is given by $\frac{m}{100}$

The probability that a car is lemon and it is tested is given by $\frac{n}{m}$

For a conditional probability, the probablility of event A given event B is given by:

$P(A|B)= \frac{P(A\cap B)}{P(B)}$

Therefore, the probability that a car is lemon, given that it is tested is given by.

$P(lemon|tested)= \frac{P(lemon\, and\, tested)}{P(tested)} \\ \\ = \frac{ \frac{n}{m} }{ \frac{m}{100} } = \frac{n}{m} \times \frac{100}{m} = \frac{100n}{m^2}$

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3 years ago

Describe the graph of a linear equation written in the form Ax + By = C when C=0.

Zinaida [17]

Answer:

I'm confused

Step-by-step explanation:

5 0

2 years ago