Answer:
(A) 0.297
(B) 0.595
Step-by-step explanation:
Let,
H = a person who suffered from a heart attack
G = a person has the periodontal disease.
Given:
P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15
Compute the probability that a person has the periodontal disease as follows:

(A)
The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.
(B)
Now if the probability of a person having a heart attack is, P (H) = 0.38.
Compute the probability that a person has the periodontal disease as follows:

Compute the probability of a person having a heart attack given that he or she has the disease:

The probability of a person having a heart attack given that he or she has the disease is 0.595.
Sorry bro, maybe next time :/
Answer:
2/3 min
Step-by-step explanation:
We can write these as equations
so 8-2.5x=5-0.5x
We isolate x by subtracting both sides by 5
3-2.5x=0.5x
add 2.5x to both sides
3=2x
divide both sides by 2
x=2/3min
(plz give brainliest)
Lets take away 2 white chips...
8 black and 4 white...total of 12 chips
P(black) = 8/12 = 2/3
remove 2 white chips <==