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Alex787 [66]
3 years ago
6

Do what it says pls will give brainliest

Mathematics
1 answer:
algol133 years ago
4 0
It’s basically x=-1
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An advertisement says that 4 out of 5 doctors prefer a certain product. what percent of doctors do not like that product
Nina [5.8K]

\dfrac{5}{5}  -  \dfrac{4}{5}  =  \dfrac{1}{5}

\dfrac{1}{5}  \times 100\% = 20\%


Answer : 20% of doctors do not like that product.

Hope this helps. - M
4 0
3 years ago
Read 2 more answers
Approximately 40% of the calls to an airline reservation phone line result in a reservation being made. (round to three decimal
IRISSAK [1]

Answer:

The probability that none of the 10 calls result in a reservation is 0.60%.  In turn, the probability that at least one call results in a reservation being made is 99.40%.

Step-by-step explanation:

Since approximately 40% of the calls to an airline reservation phone line result in a reservation being made, supposing an operator handles 10 calls, to determine what is the probability that none of the 10 calls result in a reservation, and what is the probability that at least one call results in a reservation being made, the following calculations must be performed:

0.6 ^ 10 = X

0.006 = X

0.006 x 100 = 0.60%

Therefore, the probability that none of the 10 calls result in a reservation is 0.60%.

100 - 0.60 = 99.40

In turn, the probability that at least one call results in a reservation being made is 99.40%.

3 0
3 years ago
Is this correct? Please help me due today.
gulaghasi [49]
The answer you just put is correct
5 0
3 years ago
A restaurant customer left ​$1.80 as a tip. The tax was 8% and the tip was ​20% of the cost including tax.
PtichkaEL [24]

Answer:The bill before tax was $8.33

Step-by-step explanation: Divide tip by portion of bill:

1.80/0.20 = 9.00

The total bill before the tip was $9.00

Divide total bill by 1+ sales tax rate:

9.00 / 1.08 = 8.33

8 0
3 years ago
Arbitron Media Research Inc. conducted a study of the iPod listening habits of men and women. One facet of the study involved th
trasher [3.6K]

Answer:

The null and alternative hypotheses are:

H_{0}:\sigma_{men} = \sigma_{women}

H_{a}:\sigma_{men} \neq \sigma_{women}

Under the null hypothesis, the test statistic is:

F=\frac{\sigma^{2}_{men}}{\sigma^{2}_{women}}

       =\frac{19^{2}}{9^{2}}

       =\frac{361}{81}

       =4.46

Therefore, the test-statistic is F=4.46

 Now the F critical value at 0.02 significance level for df1 = 10- 1 =9 and df2 = 16 - 1 =15 is:

F_{critical} = 3.303

Since F statistic is greater than the F critical value, we therefore, reject the null hypothesis and conclude that there is sufficient evidence to support the claim that there is a difference in the variation in the listening times for men and women.


7 0
3 years ago
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