In circle A, ZBAE ZDAE. What is the value of x?

Mathematics

1 answer:

mr_godi [17]2 years ago

3 0

Answer:

x = 17

Step-by-step explanation:

Assuming that angle BAE and angle DAE are congruent, we want to set the equations 3x - 24 and x + 10 together to make it like this 3x - 24 = x + 10. Subtract x on both sides to get 2x - 24 = 10. Add 24 on both sides to get to this equation 2x = 34. Divide 2 on both sides to get your x value which is 17.

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If (8, −9) and (6, −3) are the endpoints of the diameter of a circle, what is the equation of the circle?

Umnica [9.8K]

$(x-7)^{2} + (y+6)^{2} = 10$ is the equation of the required circle.

Step-by-step explanation:

Step 1 :

Let A = (8,-9) and B = (6,-3) be the endpoints of the diameter of the given circle.

We need to determine the circle's equation with this diameter

Step 2 :

The mid point of the diameter will be center of the required circle.

Let M = (x,y) be the mid point of the circle.

So we have x = (8+6)÷ 2 , y = ((-9) + (-3)) ÷ 2

M = ( 7, -6) is the midpoint of the diameter and the center of the circle.

Step 3 :

The radius of the circle is distance between midpoint and any one of the end point of the diameter that is distance between point A(8,-9) and M ( 7,-6)

Distance between the 2 points $(x_{1} ,y_{1}) and (x_{2} ,y_{2})$ is given by