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trapecia [35]
3 years ago
10

4-8m=-8-5m what is m​

Mathematics
1 answer:
faust18 [17]3 years ago
6 0

Answer:

-9m-4

Step-by-step explanation:

Move the -4 to the right hand side by adding 4 to both sides, like this: To the left hand side:

-4 + 4 = 0

9m ‹ 5m

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Sure Blame the answers
iren2701 [21]

Answer: For the model one it’s option 1 and for the other one it’s 10,000

Step-by-step explanation:

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3 years ago
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Readme [11.4K]

Answer:

1) 5

2) -4

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4) -10

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4 0
3 years ago
Using an ordered alphabet of 26 letters, how many ways are there to choose a set of six letters such that no two letters in the
mestny [16]
To find our solution, we can start off by creating a string of 27 boxes, all followed by the letters of the alphabet. Underneath the boxes, we can place 6 pairs of boxes and 15 empty boxes.The stars represent the six letters we pick. The empty boxes to the left of the stars provide the "padding" needed to ensure that no two adjacent letters are chosen. We can create this - 
\binom {21} {6}= \frac{21*20*19*18*17*16}{6*5*4*3*2*1} =21*19*17*8=54264
Thus, the answer is that there are \boxed{54264} ways to choose a set of six letters such that no two letters in the set are adjacent in the alphabet. Hope this helped and have a phenomenal New Year! <em>2018</em>
5 0
3 years ago
The height of a sunflower can be modeled by the expression H (1.02)t where t represents the number of years since it was planted
Irina18 [472]

Answer:

2%

Step-by-step explanation:

Giveb the model expression :

H = (1.02)^t

General relation:

H = (1 + rate)^t

Rate = yearly growth rate of sunflower

1 + rate = 1.02

Rate = 1.02 - 1

Rate = 0.02

Hence yearly growth rate of sunflower is :

0.02 * 100%

= 2%

2% growth per year.

3 0
3 years ago
What are all the factor pairs of 28?
baherus [9]

Answer: All the factor pairs of 28 are:

1, 2, 4, 7, 14, 28

Step-by-step explanation:

We can move from the outsides on opposite sides (->this way<-) and pair the numbers together to make sets of the number that will multiply to make 28

6 0
4 years ago
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