One number is 9 less than the other. Find the two numbers if their product is 736.

1 answer:

6 0

$x-first\ number\\x-9-second\ number\\\\x(x-9)=736\\x^2-9x-736=0\\\\\Delta=b^2-4ac\\\\\Delta=(-9)^2-4\cdot(-736)\cdot1=81+2944=3025\\\\\sqrt\Delta=55\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}\ \ x_1=\frac{9-55}{2*1}=\frac{-46}{2}=-23
\\\\ or \\
x_2=\frac{-b+\sqrt{\Delta}}{2a}\ \ x_2=\frac{9+55}{2*1}=\frac{64}{2}=32\\\\x_1\ is\ negative\ number\ so\ it\ can't\ be\ one\ of\ them\\\\32-9=23\\\\Searched\ number\ are\ 32\ and\ 23
$

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