Question

One number is 9 less than the other. Find the two numbers if their product is 736.

Answer 1

$x-first\ number\\x-9-second\ number\\\\x(x-9)=736\\x^2-9x-736=0\\\\\Delta=b^2-4ac\\\\\Delta=(-9)^2-4\cdot(-736)\cdot1=81+2944=3025\\\\\sqrt\Delta=55\\\\x_1=\frac{-b-\sqrt{\Delta}}{2a}\ \ x_1=\frac{9-55}{2*1}=\frac{-46}{2}=-23 \\\\ or \\ x_2=\frac{-b+\sqrt{\Delta}}{2a}\ \ x_2=\frac{9+55}{2*1}=\frac{64}{2}=32\\\\x_1\ is\ negative\ number\ so\ it\ can't\ be\ one\ of\ them\\\\32-9=23\\\\Searched\ number\ are\ 32\ and\ 23$