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poizon [28]
2 years ago
10

Question 1-1

Mathematics
1 answer:
sergeinik [125]2 years ago
7 0

The coordinates of A'' are A''(x,y) = (3-x, y-5).

Let be A(x,y) = (x,y), we apply the following operations to get the coordinates of A'':

Reflection over x = 2

A'(x,y) = (x,y) + 2\cdot [(2,y)-(x,y)]

A'(x,y) = (x,y) +2\cdot (2-x, 0)

A'(x,y) = (x,y) +(4-2\cdot x, 0)

A'(x,y) = (4-x, y)

Translation

A''(x,y) = (4-x, y) +(-1, -5)

A''(x,y) = (3-x, y-5)

The coordinates of A'' are A''(x,y) = (3-x, y-5).

We kindly invite to check this question on translations: brainly.com/question/12463306

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irina [24]

Answer:

12\sqrt{3} feet

Step-by-step explanation:

In a 30-60-90 triangle, the ratios of the side lengths of the triangle is 1:\sqrt{3} :2

Where 1 is the shortest leg, root(3) is the longer leg, and 2 is the hypotenuse.

First we can set x equals to the length of the original pole, and so the shorter leg has a length of x/3 and using the ratio of side lengths, we can find that:

\frac{x}{3} * \sqrt{3} = \frac{\sqrt{3} x}{3} = 12

Solving for x, we find that

x=\frac{36}{\sqrt{3} } = \frac{36 * \sqrt{3} }{\sqrt{3} * \sqrt{3} } = \frac{36  \sqrt{3} }{3} = 12\sqrt{3}

So the length of the original pole would be 12\sqrt{3} feet

If you found this answer helpful, please consider marking it as brainliest, or give it a thanks and a 5 star review. Thanks!

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