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Neko [114]
3 years ago
10

Simplifica: - 17 - 13

Mathematics
2 answers:
hammer [34]3 years ago
7 0
-30 :))))))))))))))))
patriot [66]3 years ago
3 0

Answer:

-30

Step-by-step explanation:

Just a bored teen willing to help,

as always, hope you're having a splendiferous day,

¡Adios!

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What missing angle of the figure
aniked [119]

Answer:

138

Step-by-step explanation:

152+125=277

277-135=142

around 138

4 0
3 years ago
M is the incenter of triangle ABC. Find the lengths of MD and DC. (Look at pic)
Deffense [45]

Answer:

Part 1) MD=9\ units

Part 2) DC=12\ units

Step-by-step explanation:

Step 1

Find the length of MD

we know that

The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle

so

In this problem

MD=ME=MF ------> is the radius of a circle inscribed inside the triangle

we have that

MF=9\ units

therefore

ME=9\ units

MD=9\ units

Step 2

Find the length of DC

we know that

In the right triangle MDC

Applying the Pythagoras theorem

MC^{2} =MD^{2}+DC^{2}

we have

MD=9\ units

MC=15\ units

substitute

15^{2} =9^{2}+DC^{2}

DC^{2}=225-81

DC=\sqrt{144}\ units

DC=12\ units

6 0
3 years ago
A bathtub is the shape of a rectangular prism. The dimensions are 5 1/2 ft times 2 1/2 ft times 2 3/4 ft. What is the volume of
Sav [38]

Answer:

37 \frac{13}{16}  ft^3

Step-by-step explanation:

A rectangular prism is also know as a cuboid.

The dimensions of the rectangular prism shaped bath tub are 5½ ft * 2½ ft * 2¾ ft.

The volume of a cuboid (rectangular prism) is given as:

V = L * B * H

Hence, the volume of the bath tub is:

V = 5½  * 2½ * 2¾

V = 11/2 * 5/2 * 11/4

V = 605 / 16 = 37 \frac{13}{16}  ft^3

The volume of the bath tub is 37 \frac{13}{16}  ft^3

5 0
3 years ago
Will give brainlist if correct!
Sveta_85 [38]

Answer:

A y=5

Step-by-step explanation:

5 0
3 years ago
Which two values of x are roots
FrozenT [24]
The answer is C. 

To solve these types of equations you first need to make sure that you equation is equal to 0. In this case all of the numbers are already on the same side so no work needs to be done there. Then we can get a, b and c values for the quadratic equation by looking at the coefficients. 

a = 4 (number attached to x^2)
b = -6 (number attached to x)
c = 1 (number with no variable attached)

Now we can put this into the quadratic equation. 

\frac{-b +/-  \sqrt{ b^{2} -4ac} }{2a}

\frac{6 +/- \sqrt{ -6^{2} -4(4)(1)} }{2(4)}

\frac{6 +/- \sqrt{20} }{8}
6 0
3 years ago
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