All categories

2 years ago

Using the graph as your guide, complete the following statement.

Mathematics

1 answer:

Mama L [17]2 years ago

8 0

There Is no picture so I can see what you are talking about

You might be interested in

How many hours of sleep do you get each night? Is this a statistical question

noname [10]

Answer:

Yes.

Step-by-step explanation:

This is a statistical question because a statistical question is a question that can be answered by collecting data that vary. The question that you provided would have different answers from different people.

Another example of a statistical question could be: "How old are the students at my school?" This would be statistical because once again, the ages will vary from different people.

4 0

3 years ago

Evaluate the line integral, where C is the given curve. (x + 6y) dx + x2 dy, C C consists of line segments from (0, 0) to (6, 1)

Dima020 [189]

Split $C$ into two component segments, $C_1$ and $C_2$ , parameterized by

$\mathbf r_1(t)=(1-t)(0,0)+t(6,1)=(6t,t)$

$\mathbf r_2(t)=(1-t)(6,1)+t(7,0)=(6+t,1-t)$

respectively, with $0\le t\le1$ , where $\mathbf r_i(t)=(x(t),y(t))$ .

We have

$\mathrm d\mathbf r_1=(6,1)\,\mathrm dt$

$\mathrm d\mathbf r_2=(1,-1)\,\mathrm dt$

where $\mathrm d\mathbf r_i=\left(\dfrac{\mathrm dx}{\mathrm dt},\dfrac{\mathrm dy}{\mathrm dt}\right)\,\mathrm dt$

so the line integral becomes

$\displaystyle\int_C(x+6y)\,\mathrm dx+x^2\,\mathrm dy=\left\{\int_{C_1}+\int_{C_2}\right\}(x+6y,x^2)\cdot(\mathrm dx,\mathrm dy)$

$=\displaystyle\int_0^1(6t+6t,(6t)^2)\cdot(6,1)\,\mathrm dt+\int_0^1((6+t)+6(1-t),(6+t)^2)\cdot(1,-1)\,\mathrm dt$

$=\displaystyle\int_0^1(35t^2+55t-24)\,\mathrm dt=\frac{91}6$

6 0

3 years ago

So llike a lil bit of help here?????

dimulka [17.4K]

Answer:

they saved the same amount of money each month

Step-by-step explanation:

5 0

3 years ago

There are 96 students in a speech contest. Yesterday, 1/4 of them gave their speeches. Today, 1/8 of the remaining students gave

sattari [20]

5/8 still havent given their speech or 60 students

6 0

3 years ago

Read 2 more answers

If you randomly choose two letters from the word "JANUARY ", find the probability that you choose letter J first and then A afte

miss Akunina [59]

Answer:

2.0%

Step-by-step explanation:

The probability of two events happening in the sequence is calculated by multiplying the probability of each event happening separately by one another. Since there are a total of 7 letters in this word then the probability of choosing one letter correctly is $\frac{1}{7}$ . Since the first letter is replaced before choosing the second letter the probability remains the same. Therefore, the sequence would be the following...

$\frac{1}{7} * \frac{1}{7}$ = 0.020164 or 2.0%

This is an independent scenario because it does not depend on any external factors and under these circumstances the percentage will remain the same.

3 0

3 years ago