The correct question is
<span>Given cos theta=4/9 and csc theta < 0 find sin theta and tan theta
</span>
we know that
csc theta=1/sin theta
if csc theta < 0
then
sin theta < 0
we have that
<span>cos theta=4/9
we know that
sin</span>² theta+cos² theta=1
so
sin² theta=1-cos² theta-----> 1-(4/9)²----> 1-(16/81)----> 65/81
sin theta=-√(65/81)---->-√65/9
the answer Part a) is
sin theta=-√65/9
Part b) find tan theta
tan theta=sin theta/cos theta
tan theta=(-√65/9)/(4/9)-----> tan theta=-√65/4
the answer part b) is
tan theta=-√65/4
To solve this, what you will need to do is find the solution of one variable and then substitute it and solve for the other.
Here’s how to solve:
y+2x=4
-2x -2x
y=4-2x
4-2x + 2x =4
4=4
So if you’re trying to see if it is true, then your answer is that it’s true.
If you’re trying to find the linear equation, then your answer is y=-2x+4.
First notice that the triangle with sides
and the triangle with sides
are similar. This is true because the angle between sides
in the smaller triangle is clearly
, while the angle between sides
in the larger triangle is clearly
. So the triangles are similar with sides
corresponding to
, respectively.
Now both triangles are
, which means there's a convenient ratio between its sides. If the length of the shortest leg is
, then the length of the longer leg is
and the hypotenuse has length
.
Since
is the shortest leg in the larger triangle, it follows that
, so
Answer:
EVERYONE REPORT ME PLEASE
Answer:
278.773622 or 300 if rounded
Step-by-step explanation:
The area of a circle is:
π (Pi) times the Radius squared:
A = π r2
or, when you know the Diameter:
A = (π/4) × D2
or, when you know the Circumference:
A = C2 / 4π
