All categories

2 years ago

Simplify 5-2(×-3) and (m+5)(m+5)

Mathematics

1 answer:

Elanso [62]2 years ago

5 0

Answer:

Step-by-step explanation:

5 - 2(x - 3) and (m+5)(m+5)

$5 - 2(x-3)\\5 - 2x + 6\\-2x + 11$

$(m+5)(m+5)\\m^2+5m+5m+25\\m^2+10m+25$

Hope this helps!

You might be interested in

Write a real world situation of |x-14|=3

natita [175]

X -14 +14={3+14}
×=17
answer is 17 .

7 0

3 years ago

Find the probability of rolling a 4 or less on the first die, and a 5 or less on the second die

bearhunter [10]

Answer:

first dice-4/6

second dice-5/6

Step-by-step explanation:

if you have six possible outcomes for the first dice and you want it to roll 1 thru 4 then you have a four out of six chance and you have a 5 out of six chance for the second dice

3 0

3 years ago

The digit which has a value of tenth in 35.427 is

inna [77]

Answer:

Step-by-step explanation:

35.427 the tens place is after 35. and four is there, so 4 is in the tenths place

8 0

2 years ago

What is the answer for 9/49 plus 19/21?

Schach [20]

Answer:

160/147

Step-by-step explanation:

6 0

3 years ago

If f(x) = 2x2 + 1 and g(x) = x2 – 7, find (f – g)(x).

nadya68 [22]

Answer: The required value is

$(f-g)(x)=x^2+8.$

Step-by-step explanation: The given functions are:

$f(x)=2x^2+1,\\\\g(x)=x^2-7.$

We are given to find the value of $(f-g)(x).$

We know that, if s(x) and t(x) are any two functions of a variable x, then we have

$(s-t)(x)=s(x)-t(x).$

Therefore, we have

$(f-g)(x)\\\\=f(x)-g(x)\\\\=(2x^2+1)-(x^2-7)\\\\=2x^2+1-x^2+7\\\\=x^2+8.$

Thus, the required value is

$(f-g)(x)=x^2+8.$

5 0

3 years ago

Simplify 5-2(×-3) and (m+5)(m+5)​

Simplify 5-2(×-3) and (m+5)(m+5)