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shepuryov [24]
2 years ago
12

I need the answer please asp

Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
8 0

Answer:

The answer is a isosceles right I think.

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Mapping congruent Triangles
Snezhnost [94]
The answer is b so mark it down
7 0
3 years ago
Read 2 more answers
If necessary, combine like terms. (x-10)(x-10)
NeTakaya

Answer:

x^2 − 20x + 100

Step-by-step explanation:

7 0
3 years ago
13. Find the surface area of each figure to the nearest tenth. Show your work.
stiv31 [10]
A. The figure is a triangular pyramid. You can findits surface area by adding up the area of the three faces of the triangle and the area of the base. A derived formula also is used where the SA is equal to 12 times the perimeter of base times the slant height, added to that is the area of the base. The area of the square base is s^2. Its perimeter is 4s.

SA of Pyramid = 12*P*l + s^2
SA of Pyramid = 12*4s*l + 16^2
SA of Pyramid = 12*4(16)*(17) + (16)^2
SA of Pyramid = 11,008 square inches

b.) The formula for the SA of a cone is: 

SA of cone = πr[r+√(h^2+r^2)]
SA of cone = π(3)[(3+√(8^2+3^2)]
SA of cone = 108.8 square inches
7 0
3 years ago
Read 2 more answers
Find the sale price when the original price is $37.00 and the discount rate is 44%.
nexus9112 [7]
Sale price = original price - discount
discount = 44% of original price = 44% of $37 = 0.44 x 37 = $16.28

Sale price = $37 - $16.28 = $20.72
5 0
3 years ago
One of the loudest sounds in recent history was that made by the explosion of Krakatoa on August 26-27, 1883. According to barom
liraira [26]

Answer:

150.51 dB

Step-by-step explanation:

Data provided in the question:

decibel level of sound at 161 km distance = 180 dB

d₁ = 161 km

d₂ = 4800 km

I₁ = 180 db

The formula for intensity of sound is given as:

I = 10\log(\frac{I_2}{I_1})

and the relation between intensity and distance is given as:

I ∝ \frac{1}{d^2}

or

Id² = constant

thus,

I₁d₁² = I₂d₂²

or

\frac{I_2}{I_1}=\frac{d_1}{d_2}

therefore,

I = 10\log(\frac{d_1}{d_2})^2

or

I = 10\times2\times\log(\frac{161}{4,800})

or

I = 20 × (-1.474)

or

I = -29.49

Therefore,

the decibel level on Rodriguez Island, 4,800 km away

= 180 - 29.49

= 150.51 dB

8 0
2 years ago
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