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2 answers:
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Answer:
Carmen's score is 75 strokes.
Linda's score is 81 strokes.
Step-by-step explanation:
Let the score of Linda be "x".
<em>It is given that Carmen's golf score is 6 strokes less than Linda's.</em>
Thus, Carmen's score is (x-6).
The total score of the girls is
=
The total score is given to be 156.
Thus, the equation becomes,
<em>Thus Linda's score is 81 and Carmen's score is (156-81) 75.</em>
Answer:
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error of the interval is given by:
In this problem, we have that:
99.5% confidence level
So , z is the value of Z that has a pvalue of
, so
.
Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?
This is n when M = 0.07. So
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07