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zalisa [80]
2 years ago
7

Simplify the following expression. (38x+61y) - (3x- 11y)

Mathematics
2 answers:
zmey [24]2 years ago
4 0

Answer:

35x+72y

Step-by-step explanation:

(38x+61y)-(3x-11y)\\38x+61y-3x+11y\\35x+72y\\

Brainliest if it helped you!

Mashcka [7]2 years ago
4 0

Answer:

please see the picture above

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River C is 300 Miles Longer than River D. If the sum of their lengths is 5,570 miles, what is the length of each river?
d1i1m1o1n [39]
x-\ length\ of\ river\ D\\
x+300-\ length\ of\ river\ C\\\\
5570=x+x+300\\
5570=2x+300\ \ \ | subtract\ 300\\5270=2x\ \ \ | divide\ by\ 2\\x=2635\\\\
River\ C\ is\ 2935miles\ long\ and\ river\ D\ 2635\ miles\ long.
6 0
3 years ago
Someone help me pleaseeeee
Rus_ich [418]

Answer:

5. Plane P

6. Line segment DB

7. Line CE

11. Ray BE (with an arrow on top from left to right) and Ray EC (with an arrow on top from left to right)

5 0
2 years ago
\angle1=9x+5 what is angle 1?
Archy [21]

Answer:

x = -5/9

Step-by-step explanation:

9x + 5 = 0

x = -5/9

if this is incorrect then ur question is missing something

3 0
2 years ago
drug sniffing dogs must be 95% accurate in their responses because their handlers don't want them to miss durgs and also don't w
GenaCL600 [577]

Answer:

95% Confidence interval:  (0.8449,0.9951)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 50

Number of times the dog is right, x = 46

\hat{p} = \dfrac{x}{n} = \dfrac{46}{50} = 0.92

95% Confidence interval:

\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

Putting the values, we get:

0.92 \pm 1.96(\sqrt{\dfrac{0.92(1-0.92)}{50}})\\\\ = 0.92\pm 0.0751\\\\=(0.8449,0.9951)

(0.8449,0.9951) is the required 95% confidence interval for the proportion of times the dog will be correct.

7 0
2 years ago
Use counting to determine the whole number that corresponds to the cardinality of these sets:______. (a) A= (xl x € Nand 20.<
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

Cardinality of a set is defined as number of element in a set. It is represented as n(X) where X is any set.

a) Given the set A =(x l x € N and 20.< x<27). According to the set, the set contains the values of natural numbers between 20 and 27. The values are 21, 22, 23, 24, 25 and 26

A = (21, 22, 23, 24, 25, 26)

According to the set A, it can be seen that there are 6 elements in the set, <em>this means n(A) = 6.</em>

b) Given B=(x | xeN and x+1=x)

Since natural numbers starts from 1, the first element in the set is 2 i.e 1+1

The elements of the set B = (2, 3, 4, 4...)

<em>The number of whole number in the set is therefore infinite. </em>

c) For the set C={x l xe N and (x- 1)(x - 9) = 0)

We need to get the root of the equation  (x- 1)(x - 9) = 0

x-1 = 0 and x-9 = 0

x = 1 and x = 9

Hence the element C = (1,9)

<em>The number of whole number in the set is n(C) = 2</em>

d)  D={xlx E N, H X 5 100, and x is divisible by both 5 and 8)

Given the value of x between 5 and 100, the values of x divisible by 5 = (10, 15, 20, 25, 30, 35, 40, 45, 50 , 55, 60 , 65, 70, 75, 80 85, 90, 95)

values of x divisible by 8 = (16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96)

<em>The total number of elements in both set = 29 i.e n(D) = 29 </em>

3 0
3 years ago
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