Here is the answer:))) hope this helpssss
Answer:
<em>The percentage of males are not at least 172 pounds</em>
P(X⁻ ≥ 172) = 0.26
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that 74% of 19 -year -old males are at least 172 pounds
Let 'X' be a random variable in a binomial distribution
P( X≥172) = 74% = 0.74
<em>we have to find that the percentage of males are not at least 172 pounds</em>
<u><em>Step(ii):-</em></u>
<em>The probability of males are not at least 172 pounds</em>
P(X⁻≥172) = 1- P( X≥172)
= 1- 0.74
<em> = 0.26</em>
<u><em>Final answer:-</em></u>
<em>The percentage of males are not at least 172 pounds</em>
P(X⁻ ≥ 172) = 0.26
<u><em></em></u>
You could do something simple like 5x5 and that gets you 25 and 5 is odd
