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irakobra [83]
2 years ago
8

A group of workers can plant 54 acres in 9 days. What is their rate in acres per day?​

Mathematics
1 answer:
telo118 [61]2 years ago
3 0

Answer:

6 acres per day

Step-by-step explanation:

Take the total acres planted (54) and divide the number of days (9) to get the acres per day (6)

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One solution 19x+18=-19x+18
masya89 [10]

19x + 18 = -19x + 18

19x + 19x = 18 - 18

38x = 0

x = 0

3 0
3 years ago
Plz plz help is for my brother his in first grade
Mkey [24]

4+2 = 6    a a a a + a a = a a a a a a

2+4 = 6  a a + a a a a= a a a a a a


Tommy is correct  They are both equal to 6

7 0
3 years ago
Read 2 more answers
mr.ellis has started a vegetable garden.he bought 15 bags of soil and 3 bags of fertilizer for 282.72.he realized he didnt have
ANTONII [103]

The cost of each bag of soil is $ 16.25 and the cost of each bag of fertilizer is $ 12.99.

<h3>What is the linear system?</h3>

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

Mr. Ellis has started a vegetable garden.

He bought 15 bags of soil and 3 bags of fertilizer for 282.72.

He realized he did not have enough supplies so he bought another 5 bags of soil and 2 bags of fertilizer for 107.23.

Let the cost of each bag of soil be x and the cost of a bag of fertilizer be y.

Then we have the linear equations,

15x + 3y = 282.72

5x + 2y = 107.23

On solving the equations 1 and 2, we have

x = 16.25 and y = 12.99

The cost of each bag of soil is $ 16.25 and the cost of each bag of fertilizer is $ 12.99.

More about the linear system link is given below.

brainly.com/question/20379472

#SPJ1

8 0
2 years ago
PLEASE ANSWER AND HELP
ra1l [238]
She must save $91.80.
7 0
3 years ago
A semicircle has the radius of 2 4/5. What is its area? leave your answers in term of π
Ratling [72]

Answer:

11\dfrac{13}{25}\pi

Step-by-step explanation:

r = Radius of semicircle = 2\dfrac{4}{5}=\dfrac{24}{5}\ \text{units}

Area of semicircle is given by

A=\dfrac{\pi r^2}{2}\\\Rightarrow A=\dfrac{\pi \left(\dfrac{24}{5}\right)^2}{2}\\\Rightarrow A=\dfrac{288}{25}\pi=11\dfrac{13}{25}\pi\ \text{sq. units}

The area of the semicircle is 11\dfrac{13}{25}\pi\ \text{sq. units}.

4 0
3 years ago
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