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2 years ago

Please help I will make you Brainliest (show working)

Mathematics

1 answer:

OLEGan [10]2 years ago

4 0

Answer:

Step-by-step explanation:

Garden is in the shape of triangle.

$Area of garden = \dfrac{1}{2}bh = \dfrac{1}{2}*10*6 = 5 *3 = 15 \ m^{2}$

Drive way:

length = 4 + 10 = 14m

Width = 3 m

Area = length * width = 14 * 3 = 42 sq.m

Perimeter of the property:

Length = 14 m

Width = 3 + 9 + 6 = 18 m

Perimeter = 2*(length + width) = 2*(14 + 18) = 2 * 32 = 64 m

You might be interested in

What’s the area of 36 square meters perimeter of 30 meters what’s the width and length of those?

Anvisha [2.4K]

≠ means not equal to
L x w = 36
2L + 2w = 30

1. Find the multiples of 36

1 and 36
2 and 18
3 and 12
4 and 9
6 and 6

2. Figure out which set of numbers multiplied by 2 equals 30.

For 1 and 36:
2(1) + 2(36) = 2 + 72 = 74 ≠ 30

For 2 and 18:
2(2) + 2(18) = 4 + 32 = 36 ≠ 30

For 3 and 12:
2(3) + 2(12) = 6 + 24 = 30

So your answer is 3 and 12

3 0

3 years ago

At the coffee shop, the ratio of cups of coffee sold to muffins was 2:7. If the shop sold 84 muffins, how many cups of coffee di

neonofarm [45]

Answer:

Step-by-step explanation:

84 divided by 7 equals 12.

12x2=24.

24 cups of coffe were sold.

8 0

3 years ago

Plz help I have no idea how to answer it

saveliy_v [14]

5. Answer: see explanation

Step-by-step explanation:

If the roots are m and 3m, then x = m and x = 3m

⇒ x - m = 0 and x - 3m = 0

⇒ (x - m)(x - 3m) = 0

⇒ x² - 4mx + 3m² = 0

Since x² + px + q = 0 then p = -4m and q = 3m²

3p² = 3(-4m)² 16q = 16(3m²)

= 3(16m²) = 48m²

= 48m²

3p² = 48m² = 16q ⇒ 3p² = 16q

**********************************************************************************************

6. Answer: 8 or 18

Step-by-step explanation:

The Area of the entire rectangle (A = L × w) is 12 × 10 = 120

The Area of the shaded region is 72, so the Area of the non-shaded region is 120 - 72 = 48.

There are two non-shaded triangles.

Bigger non-shaded Δ: L = 12-x, w = 10 ⇒ $A = \dfrac{10(12-x)}{2}$
Smaller non-shaded Δ: L = x, w = x ⇒ $A=\dfrac{x(x)}{2}$

Combine the Areas of both triangles and set it equal to the Area of the non-shaded region:

$\dfrac{x(x)}{2}+\dfrac{10(12-x)}{2}=48\\\\\\\dfrac{x^2}{2}+\dfrac{120-10x}{2}=48\\\\\\\dfrac{x^2-10x+120}{2}=48\\\\\\x^2-10x+120=96\\\\x^2-10x+24=0\\\\(x-4)(x-6)=0\\\\x - 4 = 0\quad or\quad x-6=0\\x=4\qquad or\qquad x=6\\\\\text{Based on the image provided, it appears that the x-value will be the}\\\text{smallest of the two possible solutions (4), but both solutions are valid.}$