Answer:
The ball will go to maximum height of 56.25 meters.
Step-by-step explanation:
It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec
Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :
h = 0
..............(1)
We need to find the maximum height reached by the ball. For maximum height,
t = 1.875 seconds
Put the values of t in equation (1). So,
h(t) = 56.25 meters
So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.
