1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dvinal [7]
3 years ago
8

Martin earned the following scores on his last five tests.

Mathematics
1 answer:
Arada [10]3 years ago
8 0
IQR= 18 is the interquartile range of his scores.
You might be interested in
Find the distance between the points (-3,14) and (4,-10)
Jobisdone [24]

Answer:

The answer is -3.4. If you have to round it, round it down to 3.

Step-by-step explanation:

7 0
3 years ago
The average yearly precipitation for Gulfport,
ivanzaharov [21]
5.441 inches every month I’m pretty sure
8 0
3 years ago
Put the numbers in order least to greatest!
Alenkinab [10]

Answer:

-2.4

-0.8

0.2

0.9

1.6

Step-by-step explanation:

I just know.

6 0
3 years ago
Read 2 more answers
In a clinical study, volunteers are tested for a gene that has been found to increase the risk for a disease. The probability th
MrRa [10]

Answer:

a) 0.984

b) 20 people

Step-by-step explanation:

a)

If The probability that a person carries the gene is 0.1, then in a sample of 20 people, 2 should carry the gene.

Now, we want to know how many samples there are with this property.

Since we have 20 elements where 18 are alike (do not carry the gene) and 2 are alike (carry the gene), we have to compute the number of permutations of 20 elements in which 18 are alike and 2 are alike. This number is

\frac{20!}{18!2!}=190

In this 190 20-tuples there are only 3 where the 2 carriers of the gene are in the first 3 places, namely

(1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(1,0,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

(0,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0)

where 1=carries the gene, 0=does not carry the gene.

So there are 190-3 = 187 elements in which the first 3 elements have no 2 carriers, hence the probability that 4 or more people will have to be tested until 2 of them with the gene are detected is 187/190 = 0.984 (98.4%) rounded to three decimal places.

b)

Given that the probability that a person carries the gene is 0.1, then in a sample of 20 people, 20*0.1 = 2 should carry the gene.

4 0
3 years ago
Its still glitched pls help im stuck in this menu
yan [13]
Try logging out and then logging back in
Or refresh the page
3 0
3 years ago
Other questions:
  • Please help me! Thank you!
    5·1 answer
  • You own a hamburger franchise and are planning to shut down operations for the day, but you are left with 9 bread rolls, 13 defr
    10·1 answer
  • What is 12x²y - 8x²y² + 11x²y - 4x³y² - 9xy² simplified?
    9·1 answer
  • For the pair of points, find the slope of the line that passes through both points.
    9·1 answer
  • What is the degree of the polynomial?<br> 2x2 + 3x + 1
    8·1 answer
  • 3(2y-3)=27 what is my answer
    11·2 answers
  • Dina was running for two hours at a speed of 6 miles per hour. How far did she run?
    9·2 answers
  • -(-2)^2<br><br>I can't do it because it confuses me​
    10·1 answer
  • HELP PLEASEE EMERGENCY <br> I WILL GIVE BRAINIEST
    15·2 answers
  • The midpoint of CD is (-3,4) and one endpoint is (2,5). What is the coordinate of the other
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!