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Mamont248 [21]
3 years ago
13

PLS HELP ASAP TY I FORGOT

Mathematics
2 answers:
Sonja [21]3 years ago
8 0

Answer:

2. The square of a number taken from twenty

Step-by-step explanation:

lapo4ka [179]3 years ago
5 0

Answer:

"the square of a number taken from twenty."

Step-by-step explanation:

20 - n^2 in words is "the square of a number taken from twenty."  "Taken from" indicates subtraction; we subtract n^2 from 20 in this example.

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Which of the following equations is of a parabola with a vertex at (0, 6)?
VMariaS [17]

Answer:

y = x^2 + 6

Step-by-step explanation:

please type the answers correctly next time.

If you don't know how to type x^{2} like this, then type it like this "x^2"

4 0
3 years ago
Read 2 more answers
BRUH HELP
TEA [102]

Answer:

(E) 9

Step-by-step explanation:

I found what numbers worked in all three cases. I found that when a = 4  b = 5  c = 0, all of the equations were satisfied.

Equation 1   4 + 5 = 9

Equation 2  4 + 0 = 4

Equation 3  5 + 0 = 5

Also, a + b+ c or 4 + 5 + 0 = 9

If these answers are correct, please make me Brainliest!

4 0
4 years ago
PLEASE HELP ME WITH THIS
AURORKA [14]

Answer:

C

Step-by-step explanation:

Hope this helps please consider making me brainliest!

3 0
3 years ago
Gas price dropped to 2.84 today yesterday’s price was 2.90 find the percentage decrease
IRISSAK [1]
Well, yesterday was 2.90 and today is 2.84, it dropped 6 pennies or $0.06.

now, if we take 2.90 to be the 100%, how much is 0.06 off of it in percentage?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
2.90&100\\
0.06&p
\end{array}\implies \cfrac{2.90}{0.06}=\cfrac{100}{p}\implies p=\cfrac{0.06\cdot 100}{2.90}
4 0
3 years ago
If f(x)=3-2x and g(x)=1/x+5, what is the value of [f/g](8)
IrinaVladis [17]
<span>f(x)=3-2x
</span><span>f(8)=3-2(8) = 3 -16 = -13

</span><span>g(x)=1/x+5
</span><span>g(8)=1/8+5 = 1/8 + 40/8 = 41/8

</span><span>[f/g](8) = -13  / (41/8) = -13 * (8/41) = -104/41 = -2 22/41</span>
7 0
4 years ago
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