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Elodia [21]
3 years ago
14

A particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls invol

ve fax messages, and consider a samp what is the probability that exactly 6 of the calls involve a fax message?
Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

0.1091 or 10.91%

Step-by-step explanation:    

We have been given that a particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls involve fax messages and consider a sample of 20 calls. We are asked to find the probability that exactly 6 of the calls involve a fax message.  

We will use Bernoulli's trials to solve our given problem.

P(X=x)=^nC_x\cdot P^x(1-P)^{n-x}

P(X=6)=^{20}C_6\cdot (0.20)^6(1-0.20)^{20-6}

P(X=6)=\frac{20!}{6!(20-6)!}\cdot (0.20)^6(0.80)^{14}

P(X=6)=\frac{20!}{6!(14)!}\cdot (0.000064)(0.04398046511104)

P(X=6)=38760\cdot (0.000064)(0.04398046511104)

P(X=6)=0.1090997009730

P(X=6)\approx 0.1091\\

Therefore, the probability that exactly 6 of the calls involve a fax message would be approximately 0.1091 or 10.91%.

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The correct answer is:  [B]:  " 25 a²⁵ b²⁵ " .
_________________________________________________________
<span>Explanation:
_________________________________________________________
Given the expression: 
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       </span>→  " (−5a⁵b⁵)² (a³b³)⁵  " ;   Simplify.
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Let us being by examining:
______________________________________
       →    "(−5a⁵b⁵)² " . 

→  "(−5a⁵b⁵)²  = (-5)² * (a⁵)² * (b⁵)²  = (-5)(-5) * a⁽⁵ˣ²⁾ * b⁽⁵ˣ²⁾  = 25a⁽¹⁰⁾b⁽¹⁰⁾ ;

{Note the following properties of exponents:
    (xy)ⁿ = xⁿ * yⁿ ; 

    (xᵃ)ᵇ = x⁽ᵃ * ᵇ) ; 

    (xᵃ) * (xᵇ) = x⁽ᵃ ⁺ ᵇ⁾ .}.
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Then, we examine:
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      →    "(a³b³)⁵ " .

→  "(a³b³)⁵ = a⁽³ˣ⁵⁾b⁽³ˣ⁵⁾ = a⁽¹⁵⁾b⁽¹⁵⁾ .
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So:   " (−5a⁵b⁵)² (a³b³)⁵ = (-5)a⁽¹⁰⁾b⁽¹⁰⁾ * a⁽¹⁵⁾b⁽¹⁵⁾  " ; 
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          →  " 25a⁽¹⁰⁾b⁽¹⁰⁾ * a⁽¹⁵⁾b⁽¹⁵⁾ " ; 

→  " 25a⁽¹⁰⁾b⁽¹⁰⁾ * a⁽¹⁵⁾b⁽¹⁵⁾ ;
 
               =  25a⁽¹⁰⁾ a⁽¹⁵⁾b⁽¹⁰⁾ b⁽¹⁵⁾  ;

               =  25a⁽¹⁰ ⁺¹⁵⁾ b⁽¹⁰⁺¹⁵⁾ ;

               =  25a⁽²⁵⁾ b⁽²⁵⁾ ; 
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