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Elodia [21]
3 years ago
14

A particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls invol

ve fax messages, and consider a samp what is the probability that exactly 6 of the calls involve a fax message?
Mathematics
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

0.1091 or 10.91%

Step-by-step explanation:    

We have been given that a particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls involve fax messages and consider a sample of 20 calls. We are asked to find the probability that exactly 6 of the calls involve a fax message.  

We will use Bernoulli's trials to solve our given problem.

P(X=x)=^nC_x\cdot P^x(1-P)^{n-x}

P(X=6)=^{20}C_6\cdot (0.20)^6(1-0.20)^{20-6}

P(X=6)=\frac{20!}{6!(20-6)!}\cdot (0.20)^6(0.80)^{14}

P(X=6)=\frac{20!}{6!(14)!}\cdot (0.000064)(0.04398046511104)

P(X=6)=38760\cdot (0.000064)(0.04398046511104)

P(X=6)=0.1090997009730

P(X=6)\approx 0.1091\\

Therefore, the probability that exactly 6 of the calls involve a fax message would be approximately 0.1091 or 10.91%.

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nataly862011 [7]

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area = 40.8 cm²

Step-by-step explanation:

The figure consists of a rectangle and a triangle.

area of rectangle = 12 × 2.4 = 28.8 cm²

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8 0
3 years ago
The average gasoline price of one of the major oil companies in Europe has been $1.25 per liter. Recently, the company has under
Ann [662]

Answer:

t=\frac{1.20-1.25}{\frac{0.14}{\sqrt{49}}}=-2.50    

Step-by-step explanation:

Data given and notation  

\bar X=1.20 represent the sample mean given

\sigma = 0.14 represent the population standard deviation

n=49 sample size  

\mu_o =1.25 represent the value that we want to test

t would represent the statistic (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean for the gasoline prices is lower than 1.25, the system of hypothesis would be:  

Null hypothesis:\mu \geq 1.25  

Alternative hypothesis:\mu < 1.25  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{1.20-1.25}{\frac{0.14}{\sqrt{49}}}=-2.50    

5 0
3 years ago
high school the high school graduating class of 2010 was 260 people . 5 years later the high school graduating class was 320 peo
pogonyaev

Answer:

Approximately 23%

Step-by-step explanation:

we know that

The high school graduating class of 2010 was 260 people

5 years later the high school graduating class was 320 people

In this problem

260 people represent the 100%

so

using proportion

Find out what percentage represent the difference (320-260)=60 people

Let

x -----> the percentage

\frac{260}{100\%}=\frac{60}{x}\\\\x=100\%(60)/260\\\\x=23.08\%

4 0
3 years ago
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