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3 years ago

10

Jordan wants to solve the following system using the elimination method:

2 answers:

denis-greek [22]3 years ago

7 0

In the first equation, we have 3y. In the second equation we have y.

If we multiply the second equation by 3, then if we subtract both the equations, we will be able to eliminate y.

If we multiply the second equation by -3, then if we add both the equations, we will be able to eliminate y.

The answer to your question is: 3 and -3.

Marysya12 [62]3 years ago

6 0

Answer:

The answer is -3.

Step-by-step explanation:

I just took the test, and this is the correct answer.

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M_6 is (2x – 5)º and m_8 is (x + 5)º.

HACTEHA [7]

m_6 + m_8 = 180º because they form a straight line.

So, (2x-5) + (x+5) = 180

3x = 180

x = 60

So, m_115º (2•60 - 5 = 115)

Also, because the two lines are parallel m_6 = m_3 by alternate interior angles.

So, m_3 = 115º

4 0

2 years ago

How do you solve 28-2.2x=11.6x-54.8??

malfutka [58]

28 - 2.2x = 11.6x - 54.8
28 + 54.8 = 11.6x + 2.2x
82.8 = 13.8x
82.8 / 13.8 = x
6 = x
or x = 6

6 0

3 years ago

Sophie [7]

<u>Part 1</u>

<u /> $(f\circ g)(x)=f(\sqrt{x})=4\sqrt{x}+1$

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus, the domain is $\boxed{[0, \infty)}$

<u>Part 2</u>

<u /> $(g \circ f)(x)=g(4x+1)=\sqrt{4x+1}$

We need to make sure the radical is defined, meaning the radicand has to be non-negative. Thus,

$4x+1 \geq 0\\\\4x \geq -1\\\\x \geq -\frac{1}{4}$

Thus, the domain in interval notation is $\boxed{\left[-\frac{1}{4}, \infty)}$

8 0

2 years ago

Solve the system of linear equations by ellmination. 5x + 9y = -11 3x + 9y = -3 A. (-4,-1) -B. (-1, –4) C. (-4,1) D. (1,-4)

valentina_108 [34]

Answer:

Step-by-step explanation:

5x + 9y = -11

3x + 9y = -3

5x + 9y = -11

-3x - 9y = 3

2x = -8

x = -4

-12 + 9y = -3

9y = 9

y = 1

(-4, 1)

Answer is C

5 0

3 years ago

Anyone know the answer to this geometry question?

babymother [125]

I do not answer I mean College and I passed it

3 0

3 years ago