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MrRissso [65]
3 years ago
10

Jordan wants to solve the following system using the elimination method:

Mathematics
2 answers:
denis-greek [22]3 years ago
7 0
In the first equation, we have 3y. In the second equation we have y.

If we multiply the second equation by 3, then if we subtract both the equations, we will be able to eliminate y.

If we multiply the second equation by -3, then if we add both the equations, we will be able to eliminate y.

The answer to your question is: 3 and -3.
Marysya12 [62]3 years ago
6 0

Answer:

The answer is -3.

Step-by-step explanation:

I just took the test, and this is the correct answer.

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Over what interval is the function in this graph decreasing
posledela
C) 

you look at were the graph starts to decrease then look at the X-VALUE not the y-value

the x-val at the start of the decrease is -3 and at the end of it it is 2 therefor -3 \leq x \leq 2
6 0
4 years ago
Read 2 more answers
Is triangle ABC similar to triangle DEF? why or why not.
Lana71 [14]

Answer:

D

Step-by-step explanation:

Two triangles are congruent if they have the same three sides in proportion and they have exactly the same angles.

If the angles are different, the triangles are not similar.

3 0
4 years ago
What is 50% off $55.oo?
AnnZ [28]
50% of $55 = $27.50

Hope This Helps You!
Good Luck Studying :)
6 0
3 years ago
Which are the solutions of x^2 = –11x + 4?
strojnjashka [21]

This is a quadratic equation, i.e. an equation involving a polynomial of degree 2. To solve them, you must rearrange them first, so that all terms are on the same side, so we get

x^2 + 11x - 4 = 0

i.e. now we're looking for the roots of the polynomial. To find them, we can use the following formula:

x_{1,2} = \frac{-b\pm\sqrt{b^2-4ac}}{2}

where x_{1,2} is a compact way to indicate both solutions x_1 and x_2, while a,b,c are the coefficients of the quadratic equation, i.e. we consider the polynomial ax^2+bx+c.

So, in your case, we have a=1,\ \ b=11,\ \ c=-4

Plug those values into the formula to get

x_{1,2} = \frac{-11\pm\sqrt{121+16}}{2} = \frac{-11\pm\sqrt{137}}{2}

So, the two solutions are

x_1 = \frac{-11+\sqrt{137}}{2}

x_2 = \frac{-11-\sqrt{137}}{2}

3 0
3 years ago
I need help on that question ​
Anika [276]

Answer:

the required answer is

80 \sqrt{3}

Step-by-step explanation:

here's the solution : -

=》

4 \sqrt{5}  \times 4 \sqrt{15}

=》

4 \sqrt{5}  \times 4 \sqrt{5}  \times  \sqrt{3}

=》

4 \times 4 \times 5 \times  \sqrt{3}

=》

80 \sqrt{3}

3 0
3 years ago
Read 2 more answers
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