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ankoles [38]
3 years ago
8

PLS Answer these questions, I have a test!

Mathematics
2 answers:
sdas [7]3 years ago
5 0

Answer:

I think the first question is A. And the second one the answer is 125 degrees. VCF is obtuse VCN is acute and NCR is right angle.

Step-by-step explanation:

Naya [18.7K]3 years ago
4 0

Answer:

D, 120 , In order obtuse acute right,

Step-by-step explanation:

the fourth one dosent have options so I cant answer that ( It can be anything other than ZMD and DMZ)

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Simplify urgently : (8x^2-5x+1)-(3x^2-x+4)!!
azamat

Answer:

5x^2 + 4x -3x

Step-by-step explanation:

we will simply open the brackets and

simply solve them according to signs they are having

6 0
4 years ago
Read 2 more answers
Question 1 (1 point)
Amanda [17]

Answer:

a) 166x.

Step-by-step explanation:

167x - x

= 166x.

3 0
3 years ago
Read 2 more answers
An earth satellite remains in orbit at a distance of 11550 km from the center of the earth. what speed would it have to maintain
marishachu [46]
<span>11,550 km has to be changed to 11,550,000 meters

G · m · t² = 4 · π² · r³  we can change that to
</span>t² = (4 · π² · r³) / <span>(G · m )
t^2 = 4*PI^2*r^3 / (G*m)
</span>t^2 = 4*PI^2*<span>(11,550,000)^3 / 6.67*10^-11*5.98*10^24kg
t^2 = </span> <span> <span> <span> 6.083*10^22 </span> </span> </span> <span><span> </span> </span> / <span> <span> <span> 3.9</span></span></span>9 * 10^14
t^2 =  <span> <span> <span> 152,500,000</span></span></span>
t = <span>12,350 seconds
</span>and its orbital distance it travels is 11,550 * 2*PI = 70,050 kilometers

Therefore, it is traveling at 70,050 km / 12,350 second which equals
5.67 km per second which  <em>is 5,670 meters per second.</em>


Source:
http://www.1728.org/kepler3a.htm



4 0
4 years ago
An apple orchard has an average yield of 40 bushels of apples per tree if tree density is 28 trees per acre. For each unit incre
Mandarinka [93]

Answer:

24 trees per acre

Step-by-step explanation:

Let x be the optimal tree density per acre and y be the number of bushels yield per tree

Since for each unit change of x from 28 trees/acre, we have 2 unit change of y from 40 bushels per tree in the reversed direction

Change of x from 28 is x - 28

Change of y from 40 is y - 40

Therefore we have y - 40 = -2(x - 28) or y = 40 - 2(x - 28) = -2x + 96

The total bushels per acre should be y bushels/tree * x tree/acre. We want to optimize this. Substitute the above equation in for y and we have

T = xy = x(-2x+96)

T = -2x^2 + 96x

To find the maximum value of this, we can take the first derivative and set it to 0

T^{'} = -4x + 96 = 0

4x = 96

x = 24

We know this is a maxima because T{''} = -4 < 0. So T is maximum when x = 24 trees per acre

7 0
4 years ago
HELP ME PLEASE!! Find R and theta with the coordinates (-3,7).
Fofino [41]

Answer:

Since r is the distance from the origin to (x,y), it is the magnitude r=√x2+y2. Alternatively, from the equation (1), one can calculate directly that x2+y2=r2cos2θ+r2sin2θ=r2(cos2θ+sin2θ)=r2.

Step-by-step explanation:

7 0
3 years ago
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