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IgorC [24]
3 years ago
13

What value of g makes the equation true? (xt7)(x-4)=x2+gx-28

Mathematics
1 answer:
Mnenie [13.5K]3 years ago
8 0

Answer:

g = 3

Step-by-step explanation:

If you distribute (x+7)(x-4) you get:

x²+3x-28

Compare it to the question:

x²+gx-28

and it becomes obvious that g = 3

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A flat screen tv at Best Buy costs $699 . The sales tax in Virginia is 5.3%. How much tax will you pay on the TV?
krok68 [10]

Answer:

736.05

Step-by-step explanation:699.00 x 5.3%=37.047

699.00 + 37.05 = 736.05

4 0
3 years ago
Read 2 more answers
6. The dimensions of a living room are 18 ft. by 15 ft. by 8ft. If air weighs 0.08 lb. per cubic foot, the weight of the air in
user100 [1]

The weight of the air in the room is 172.8 lb if the dimensions of a living room are 18 ft. by 15 ft. by 8ft.

<h3>What is a rectangular prism?</h3>

It is defined as the six-faced shape, a type of hexahedron in geometry.

It is a three-dimensional shape. It is also called a cuboid.

It is given that:

The dimensions of a living room are 18 ft. by 15 ft. by 8ft.

The volume of the living room = volume of the cuboid:

V = length×width×height

V = 18×15×8

V = 2160 cubic ft

The weight of the air = 0.08 lb. per cubic foot

The weight of the air in the room = 0.08×2160

The weight of the air in the room = 172.8 lb

Thus, the weight of the air in the room is 172.8 lb if the dimensions of a living room are 18 ft. by 15 ft. by 8ft.

Learn more about the rectangular prism here:

brainly.com/question/21308574

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7 0
2 years ago
Is negative 5/8ths more than,less than or equal to 0.27?
ollegr [7]
It is less than. Any negative number compared to a positive number will be less than.
7 0
3 years ago
What is the name of the shape of the graph of a quadratic function?
dimaraw [331]
Is this a multiple choice or no
6 0
3 years ago
An object is acted upon by the forces F1=&lt;10​,6​,4&gt; and F2=&lt;0​,3​,9&gt;. Find the force F3 that must act on the object
murzikaleks [220]

\vec F_3=\langle x,y,z\rangle is a force vector such that

\vec F_1+\vec F_2+\vec F_3=\vec0

\implies\langle10,6,4\rangle+\langle0,3,9\rangle+\langle x,y,z\rangle=\langle0,0,0\rangle

\implies\begin{cases}10+x=0\\9+y=0\\13+z=0\end{cases}\implies x=-10,y=-9,z=-13

So the missing force is

\boxed{\vec F_3=\langle-10,-9,-13\rangle}

8 0
3 years ago
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