Question

Which is most likely a covalent compound? NaCl KCl CuF2 CF4

Answer 1

CF4 is the one which is covalent  compound

explanation

CF4 compound is formed between two non metal that is between  carbon  and fluorine  and a covalent  compound  is formed when two non metal  combine by sharing. electrons. CF4  has a strong  bond strength due to the nature of carbon- fluorine  bond.

Answer 2

$\boxed{{\mathbf{C}}{{\mathbf{F}}_{\mathbf{4}}}}$ is most likely to be a covalent compound.

Further Explanation:

The bond that is formed by the mutual sharing of electrons between the bonded atoms is called a covalent bond. It is also known as a molecular bond. Covalent compounds are those compounds which are formed by the electron sharing between two or more non-metals.

Following are some of the properties of covalent compounds:

1. These are brittle solids.  

2. Low melting and boiling points.  

3. Poor conductors of heat and electricity.  

4. Low enthalpy of fusion.

Boron trichloride $\left( {{\text{BC}}{{\text{l}}_3}} \right)$ , silicon dioxide   $\left( {{\text{Si}}{{\text{O}}_2}} \right)$, and xenon hexafluoride $\left( {{\text{Xe}}{{\text{F}}_{\text{6}}}} \right)$  are some examples of covalent compounds.

In ${\text{NaCl}}$ , sodium is metal while chlorine is a non-metal. Sodium has the tendency to lose electrons by virtue of its metallic nature and chlorine has a very strong affinity for electrons due to its high electronegativity. During this process, sodium gets converted into its cation and an anion is formed by a chlorine atom. This results in the formation of an ionic bond between these two ions and therefore ${\text{NaCl}}$  is an ionic compound.

In ${\text{KCl}}$ , potassium is metal while chlorine is a non-metal. Potassium has the tendency to lose electrons by virtue of its metallic nature and chlorine has a very strong affinity for electrons due to its high electronegativity. During this process, potassium gets converted into its cation and an anion is formed by a chlorine atom. This results in the formation of an ionic bond between these two ions and therefore ${\text{KCl}}$   is an ionic compound.

In  ${\text{Cu}}{{\text{F}}_2}$, copper is metal while fluorine is a non-metal. Copper has the tendency to lose electrons by virtue of its metallic nature and fluorine has a very strong affinity for electrons due to its high electronegativity. During this process, copper gets converted into its cation and an anion is formed by a fluorine atom. This results in the formation of an ionic bond between these two ions and therefore ${\text{Cu}}{{\text{F}}_2}$  is an ionic compound.

In  ${\text{C}}{{\text{F}}_4}$, both carbon and fluorine are non-metals. Carbon has four valence electrons whereas fluorine has seven valence electrons. Both share two electrons with each other and a single covalent bond is formed between a carbon and a fluorine atom. So carbon forms four single bonds with four fluorine atoms in order to complete its octet and the octet of fluorine is also fulfilled. This bond is formed due to sharing of the electrons and therefore  ${\text{C}}{{\text{F}}_4}$ is a covalent compound.

Learn more:

1. The part of the eye similar to the film camera: brainly.com/question/3108385s  

2. The correct name of the compound: brainly.com/question/9535482

Answer details:

Grade: High School  

Subject: Chemistry  

Chapter: Ionic and covalent compounds

Keywords: NaCl, KCl, CuF2, CF4, ionic compound, covalent compound., molecular bond, covalent bond, mutual sharing, electrons, electronegativity.