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Nataliya [291]
2 years ago
14

Chemistrystate two industrial uses of hydrogen​

Chemistry
1 answer:
solniwko [45]2 years ago
8 0

Answer:

refining petroleum, treating metals, producing fertilizer, and processing foods.

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When sulfate (SO42-) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is?
o-na [289]

When sulfate (SO₄²⁻) serves as the electron acceptor at the end of a respiratory electron transport chain, the product is hydrogen sulfide (H₂S).

How sulfate acts as electon acceptor and electron donor?

  • Sulfate (SO₄²⁻) is used as the electron acceptor in sulfate reduction, which results in the production of hydrogen sulfide (H2S) as a metabolic byproduct.
  • Many Gram negative bacteria identified in the -Proteobacteria use sulfate reduction, which is a rather energy-poor process.
  • Gram-positive organisms connected to Desulfotomaculum or the archaeon Archaeoglobus also utilise it.
  • Electron donors are needed for sulfate reduction, such as hydrogen gas or the carbon molecules lactate and pyruvate (organotrophic reducers) (lithotrophic reducers).

Learn more about the Electron transport chain with the help of the given link:

brainly.com/question/24372542

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3 0
2 years ago
What is the molar mass of H2(SO4)3?​
nalin [4]

Answer:

Explanation:

The molecular mass of C2H6 is approximately 30 or [(2 x 12) + (6 x 1)]. Therefore the molecule is about 2.5 times as heavy as the 12C atom or about the same mass as the NO atom with a molecular mass of 30 or (14+16).

7 0
3 years ago
how many moles of iodine should be added to 750 grams of carbon tetrachloride to prepare a 0.24 m solution
aleksley [76]

Answer:

0.18 mol

Explanation:

Given data

  • Mass of carbon tetrachloride (solvent): 750 g
  • Molality of the solution: 0.24 m
  • Moles of iodine (solute): ?

Step 1: Convert the mass of the solvent to kilograms

We will use the relationship 1 kg = 1,000 g.

750g \times \frac{1kg}{1,000g} =0.750kg

Step 2: Calculate the moles of the solute

The molality is equal to the moles of solute divided by the kilograms of solvent. Then,

m = \frac{moles\ of\ solute }{kilograms\ of\ solvent} \\moles\ of\ solute = m \times kilograms\ of\ solvent = \frac{0.24mol}{kg}  \times 0.750kg = 0.18 mol

6 0
3 years ago
Read 2 more answers
Molar mass of A1C1 3
Kamila [148]

Answer:

Gold(III) chloride

5 0
3 years ago
A 2.40 kg block of ice is heated with 5820 J of heat. The specific heat of water is 4.18 J•g^-1•C^-1. By how much will it’s temp
MrMuchimi

Answer: The temperature rise is 0.53^0C

Explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

Q=m\times c\times \Delta T

Q = Heat absorbed by ice = 5280 J

m = mass of ice = 2.40 kg = 2400 g   (1kg=1000g)

c = heat capacity of water = 4.18J/g^0C

Initial temperature  = T_i

Final temperature = T_f  

Change in temperature ,\Delta T=T_f-T_i=?

Putting in the values, we get:

5280J=2400g\times 4.18J/g^0C\times \Delta T

\Delta T=0.53^0C

Thus the temperature rise is 0.53^0C

0 0
3 years ago
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