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1 year ago

Chemistrystate two industrial uses of hydrogen

Chemistry

1 answer:

solniwko [45]1 year ago

8 0

Answer:

refining petroleum, treating metals, producing fertilizer, and processing foods.

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According to the Octet Rule, an element is most stable with ______________ valence electrons

Len [333]

Eight because an octet has 8 electrons and when it’s full it’s stable. If it’s not full, it’s constantly sharing or borrowing electrons.

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2 years ago

Determine the mass of 2.75 moles of CaSO4. Record your work and your answer.

maw [93]

Explanation:

$RFM \: = 160 \: g \\ 1 \: mole \: weighs \: 160 \: g \\ 2.75 \: moles \: weighs \: \frac{2.75 \times 160}{1} g \\ = 440 \: g$

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2 years ago

Student carries out a titration to determine the concentration of a solution of

Nimfa-mama [501]

The concentration of the Nitric acid solution : 0.114 M

<h3>Further explanation </h3>

Titration is a procedure for determining the concentration of a solution (analyte) by reacting with another solution whose known concentration (usually a standard solution) is called the titrant. Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range

Titrations can be acid-base titration, depositional titration, and redox titration. An acid-base titration is the principle of neutralization of acids and bases

Reaction

HNO₃ + NaOH → NaNO₃ + H₂O

Concentration a standard solution of sodium hydroxide : 0.0998 mol/dm³ , and the volume = 25 cm³

moles NaOH=

$\tt mol=M\times V\\\\mol=0.0998\times 25\\\\mol=2.495~mlmoles$

<em>From the equation, mol ratio HNO₃ : NaOH = 1 : 1, so mol HNO₃ = mol NaOH=</em><em>2.495 mlmoles</em>

The volume of HNO₃ = 21.8 cm³, so the concentration :

$\tt M=\dfrac{n}{V}\\\\M=\dfrac{2.495}{21.8}\\\\M=0.114$

7 0

2 years ago

What is the percent of O in<br> CO2?

katen-ka-za [31]

Answer:

72.7% of oxygen

Explanation:

8 0

2 years ago

How many moles of hydrogen are required to react with 4.6 x 10 22 molecules of nitrogen?

V125BC [204]

Answer: 6 moles

Take a look at the balanced chemical equation for this synthesis reaction

N 2(g] + 3 H 2(g] → 2 NH 3(g]

Notice that you have a 1:3 mole ratio between nitrogen gas and hydrogen gas. This means that, regardless of how many moles of nitrogen gas you have, the reaction will always consume twice as many moles of hydrogen gas.

So, if you have 2 moles of nitrogen taking part in the reaction, you will need

2 moles N 2 ⋅ 3 moles H 2 /1 mole N 2 = 6 moles H 2

8 0

3 years ago

Chemistrystate two industrial uses of hydrogen​

Chemistrystate two industrial uses of hydrogen