All categories

3 years ago

What three tests must all theories pass to be considered a "proven" theory?

Chemistry

1 answer:

VladimirAG [237]3 years ago

7 0

In order to become a scientific theory the three categories that it must pass are the following:

1) Can the phenomena be recreated in a laboratory setting?

2) Can variables be changed, yet still result in like observations?

3) Is the phenomena truly natural or was it the result of a man-made force enacting upon it?

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If the ph of a solution is 6.2 what would the poh be

horsena [70]

PH + poH = 14
6.2 +poH = 14
poH = 7.8

7 0

3 years ago

Read 2 more answers

A hypothetical element has an atomic weight of 48.68 amu. It consists of three isotopes having masses of 47.00 amu, 48.00 amu, a

Morgarella [4.7K]

Answer : The percent abundance of the heaviest isotope is, 78 %

Explanation :

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

As we are given that,

Average atomic mass = 48.68 amu

Mass of heaviest-weight isotope = 49.00 amu

Let the percentage abundance of heaviest-weight isotope = x %

Fractional abundance of heaviest-weight isotope = $\frac{x}{100}$

Mass of lightest-weight isotope = 47.00 amu

Percentage abundance of lightest-weight isotope = 10 %

Fractional abundance of lightest-weight isotope = $\frac{10}{100}$

Mass of middle-weight isotope = 48.00 amu

Percentage abundance of middle-weight isotope = [100 - (x + 10)] % = (90 - x) %

Fractional abundance of middle-weight isotope = $\frac{(90-x)}{100}$

Now put all the given values in above formula, we get:

$48.68=[(47.0\times \frac{10}{100})+(48.0\times \frac{(90-x)}{100})+(49.0\times \frac{x}{100})]$

$x=78\%$

Therefore, the percent abundance of the heaviest isotope is, 78 %

5 0

3 years ago

Read 2 more answers

S-2-iodooctane lost his opticaly activity in soln on tratment wwithNaI. Explain

IceJOKER [234]

Answer:

Repeated SN2 reactions occur leading to the formation of a racemic mixture

Explanation:

S-2-iodooctane is a chiral alkyl halide with an asymmetric carbon atom. The presence of an asymmetric carbon atom implies that it can rotate plane polarized light and thus lead to optical isomerism. The two configurations of the compound are R/S according to the Cahn-Prelong-Ingold system.

However, when S-2-iodooctane is treated with sodium iodide in acetone, repeated SN2 reactions occur since the iodide ion is both a good nucleophile and a good leaving group. Hence a racemic modification is formed in the system with time hence we end up with (±)- Iodooctane.

5 0

3 years ago

PLEASE HELP ME, 20 POINTS

Marrrta [24]

Explanations:

Question 1: Lithium in 20.00+ g is C. or D., but 25.00+ g is D. which means this is the correct option.

I am unsure of Question 2. I don't think it is mole though.

Question 3: Boron in 25.00-30.00 g is B. or D., but 25.00 g would be C.

Question 4: 2.393 x 1024 atoms of Oxygen is 63.58 mole O. I don't know for sure, but I think this is correct.

I am NOT professional. There is a chance I am incorrect. Please reply to me if I've made a mistake.

4 0

2 years ago

given the diagram below which contains a mixture of three acids in an aqueous solution, identify the color of the sphere that re

charle [14.2K]

The acid having the yellow anion is a weak acid.

The weak acid is the acid that does not dissociate completely in solution. Strong acids are known to dissociate completely in solution. Hence, their cations and anions do not occur together in solution.

Weak acids acids do not dissociate in solution hence, we can still spot the cations connected to their anions in solution. Hence, the acid having the yellow anion is a weak acid.

Learn more: brainly.com/question/8743052

7 0

2 years ago