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svlad2 [7]
3 years ago
9

What is the GCF of 2a3 and a6​

Mathematics
1 answer:
Finger [1]3 years ago
4 0

Answer:

pls Mark brainlist

Step-by-step explanation:

Solution

Factor of 2a^3

2 × a × a × a

Factor of a^6

a × a × a × a × a × a

Therefore, the GCF would be a × a × a = a^3.

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In studies for a​ medication, 3 percent of patients gained weight as a side effect. Suppose 643 patients are randomly selected.
timofeeve [1]

Part a)

It was given that 3% of patients gained weight as a side effect.

This means

p = 0.03

q = 1 - 0.03 = 0.97

The mean is

\mu  = np

\mu = 643 \times 0.03 = 19.29

The standard deviation is

\sigma =  \sqrt{npq}

\sigma =  \sqrt{643 \times 0.03 \times 0.97}

\sigma =4.33

We want to find the probability that exactly 24 patients will gain weight as side effect.

P(X=24)

We apply the Continuity Correction Factor(CCF)

P(24-0.5<X<24+0.5)=P(23.5<X<24.5)

We convert to z-scores.

P(23.5 \: < \: X \: < \: 24.5) = P( \frac{23.5 - 19.29}{4.33} \: < \: z \: < \:  \frac{24.5 - 19.29}{4.33} ) \\  = P( 0.97\: < \: z \: < \:  1.20) \\  = 0.051

Part b) We want to find the probability that 24 or fewer patients will gain weight as a side effect.

P(X≤24)

We apply the continuity correction factor to get;

P(X<24+0.5)=P(X<24.5)

We convert to z-scores to get:

P(X \: < \: 24.5) = P(z \: < \:  \frac{24.5 - 19.29}{4.33} )  \\ =   P(z \: < \: 1.20)  \\  = 0.8849

Part c)

We want to find the probability that

11 or more patients will gain weight as a side effect.

P(X≥11)

Apply correction factor to get:

P(X>11-0.5)=P(X>10.5)

We convert to z-scores:

P(X \: > \: 10.5) = P(z \: > \:  \frac{10.5 - 19.29}{4.33} )  \\ = P(z \: > \:  - 2.03)

= 0.9788

Part d)

We want to find the probability that:

between 24 and 28, inclusive, will gain weight as a side effect.

P(24≤X≤28)=

P(23.5≤X≤28.5)

Convert to z-scores:

P(23.5  \:  <  \: X \:  <  \: 28.5) = P( \frac{23.5 - 19.29}{4.33}   \:  <  \: z \:  <  \:  \frac{28.5 - 19.29}{4.33} ) \\  = P( 0.97\:  <  \: z \:  <  \: 2.13) \\  = 0.1494

3 0
4 years ago
NEED HELP AGAIN ASAP! MATH PEOPLE ONLY. WILL GIVE BRAINLIEST, TON OF POINTS ONLY FOR THE RIGHT ANSWER.
Hoochie [10]
It seems it moves 18 degrees per second on the y axis
5 0
4 years ago
What is 4855/200 simplified
EleoNora [17]

Answer:

The answer is 2427.5

Step-by-step explanation:

The fraction consists of two numbers and a fraction bar: 4,855/200

The number above the bar is called numerator: 4,855

The number below the bar is called denominator: 200

The fraction bar means that the two numbers are dividing themselves.

To get fraction's value divide the numerator by the denominator:

Value = 4,855 ÷ 200

To calculate the greatest common factor, GCF:

1. Build the prime factorizations of the numerator and denominator.

2. Multiply all the common prime factors, by the lowest exponents.

Factor both the numerator and denominator, break them down to prime factors:

Prime Factorization of a number: finding the prime numbers that multiply together to make that number.

4,855 = 5 × 971;

4,855 is a composite number;

In exponential notation:

200 = 2 × 2 × 2 × 5 × 5 = 23 × 52;

200 is a composite number;

3 0
3 years ago
Harvey Alson invested $7,500 in a 2-year CD that pays 6% interest compounded quarterly. What is the amount of interest that Harv
irga5000 [103]
A=7,500×(1+0.06÷4)^(4×2)
A=8,448.69

Interest earned=8,448.69−7,500
Interest earned=948.69
5 0
3 years ago
Read 2 more answers
Find the value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2
soldier1979 [14.2K]

The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2

<u>Solution:</u>

Given that line is passing through point (-5, 2) and (3, r)

Slope of the line is \frac{-1}{2}

Need to determine value of r.

Slope of a line passing through point \left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right)  is given by following formula:

\text { Slope } m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}  --- eqn 1

\text { In our case } x_{1}=-5, y_{1}=2, x_{2}=3, y_{2}=\mathrm{r} \text { and } m=-\frac{1}{2}

On substituting the given value in (1) we get

\begin{array}{l}{-\frac{1}{2}=\frac{r-2}{3-(-5)}} \\\\ {\text { Solving the above expression to get value of } r} \\\\ {=>-\frac{1}{2}=\frac{r-2}{3+5}} \\\\ {=>-8=\frac{r-2}{3+5}} \\\\ {=>-8=2(r-2)} \\\\ {=>-8=2 r-4} \\\\ {=>2 r=-8+4} \\\\ {=>2 r=-4} \\\\ {=>r=\frac{-4}{2}=-2}\end{array}

Hence the value of "r" is -2

8 0
3 years ago
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