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3 years ago

5.) I somehow got $50 to buy hair dye, so I got 4 bottles of hair dye I had 5 dollars left, how

Mathematics

2 answers:

Anna71 [15]3 years ago

8 0

Answer:

The hair dye was $11.25

Step-by-step explanation:

4x+5=50

4x=45

x=11.25

Lunna [17]3 years ago

5 0

Answer:

Step-by-step explanation:

is the answer

<h2>mark me as brainlest</h2>

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Andru [333]

360 minutes i beleive

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2 years ago

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Destiny said that zero point six ÷2 = 0 .3 is she correct explain why or why not

Stells [14]

Yes. Simply, if you have $.6o, or 60 cents and you give half to someone else, you both have 30 cents or 0.3.

4 0

3 years ago

Use the equations to find the perimeter equation

Law Incorporation [45]

The perimeter of the park is 3x^2 + 37x - 4

<h3>How to determine the perimeter?</h3>

The side lengths of the triangular park are:

10x + 3x^2 - 8, 12x and 15x + 4

Add these sides to determine the perimeter

P = 10x + 3x^2 - 8 + 12x + 15x + 4

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P = 3x^2 + 10x + 12x + 15x - 8 + 4

Evaluate the sum

P = 3x^2 + 37x - 4

Hence, the perimeter of the park is 3x^2 + 37x - 4

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brainly.com/question/24571594

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6 0

2 years ago

..........................

goldfiish [28.3K]

Answer:

$\boxed{-10000}$

Step-by-step explanation:

$F(x)=\frac{1}{x}$

Let x = -10000

$F(-10000)=\frac{1}{-10000}$

$F(-10000)= -0.0001$

-0.0001 is closest to 0 when x value is -10000.

No other value can work from the other options, options B and C increase the value from 0. Option D would make the function undefined.

6 0

3 years ago

((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}$

$\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
\\\\\\
\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}$

7 0

3 years ago