Answer:
im stuck on that too man
Step-by-step explanation:
Answer:
10
Step-by-step explanation:
<h3>Calculating BC</h3><h3>BC = √2^2 + 11^2 </h3><h3>BC = √ 4+121</h3><h3>BC = √ 125 = 11.18</h3>
to find measure of angle C use sinerule
<h3>sinC/C = sinA/A</h3><h3>sinC/2= Sin90/11.18</h3><h3>SinC = 2×1/11.18</h3>
<h3>sinC = 2/11.18</h3><h3>sinC = (0.1788)</h3><h3>C = sin^-1(0.1788)</h3>
<h3>C = 10.305</h3><h3>C = 10 (approximately)</h3>
See the attached picture:
Answer:
Entries of I^k are are also identity elements.
Step-by-step explanation:
a) For the 2×2 identity matrix I, show that I² =I
![I^{2}=\left[\begin{array}{cc}1&0\\0&1\end{array}\right] \times \left[\begin{array}{cc}1&0\\0&1\end{array}\right] \\\\=\left[\begin{array}{cc}1\times 1+0\times 0&1\times 0+0\times 1\\0\times 1+1\times 0&0\times 0+1\times1\end{array}\right] \\\\=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=I%5E%7B2%7D%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%5Ctimes%201%2B0%5Ctimes%200%261%5Ctimes%200%2B0%5Ctimes%201%5C%5C0%5Ctimes%201%2B1%5Ctimes%200%260%5Ctimes%200%2B1%5Ctimes1%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
Hence proved I² =I
b) For the n×n identity matrix I, show that I² =I
n×n identity matrix is as shown in figure
Elements of identity matrix are

As square of 1 is equal to 1 so for n×n identity matrix I, I² =I
(c) what do you think the enteries of Ik are?
As mentioned above

Any power of 1 is equal to 1 so kth power of 1 is also 1. According to this Ik=I