Answer:
please give me a brainless 0
Inequality :
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
The following is as far as I get:
α1+(n−1)a−(⌊n÷m⌋×(a−b))≥x
(n−1)a−(⌊n÷m⌋×(a−b))≥x−α1
n−1−(⌊n÷m⌋×(a−b))≥x−α1a
n−(⌊n÷m⌋×(a−b))≥x−α1a + 1
Step-by-step explanation:
No 9.717 is greater than 9.707 because 9.717 would be seven hundred seven thousandths and 9.717 would be seven hundred seven teen hundredths.
Distance formula: √((y2-y1)^2+(x2-x1)^2)
Plug in the values √((4-2)^2+(6-3)^2)
√((2)^2+(3)^2) = √(4+9) = √13 = 3.6
3.6 is your answer.
Answer:
TRUE
Step-by-step explanation:
tanθ = 1/cotθ
cotθ = 0 when θ = ±(1/2)π, ±(3/2)π, … ±[(2n+1)/2]π.
∴ tanθ is undefined when θ = ±[(2n+1)/2]π.
secθ = 1/cosθ
cosθ = 0 when θ = ±(1/2)π, ±(3/2)π, , …, ±[(2n+1)/2]π.
∴ secθ is undefined when θ = ±[(2n+1)/2]π.
The tangent and secant functions are undefined for the same values of θ.
Answer:
24
Step-by-step explanation:
