Answer:
there are only 4 whole numbers whose squares and cubes have the same number of digits.
Explanations:
let 0, 1, 2 and 4∈W (where W is a whole number), then
, 
,
, 
,
, 
,
, 
.
You can see from the above that only four whole numbers are there whose squares and cubes have the same number of digits
Answer:
A
Step-by-step explanation:
This notation says that x+x+x+x+37=69
This can be simplified to say 4x+37=69
Answer:
DF = 14
Step-by-step explanation:
Andrew was wrong in the assumption that DE = EF
Segments of tangents to a circle from the same external point are congruent
That is
EF = FG = 8
Then
DF = DE + EF = 6 + 8 = 14
Area of square = atleast 36 = length *width, where l = w (since it's a square)
If A=36, l = w = 6
If A = 37, l = w = 6.08
if A =38, l = w = 6.16
So the solution set is s => 6 (s is bigger than or equal to 6)
0, 1/8, 1/4, 1/2, 1/2, 3/4, 1, 4/3, 3, 3, 7/2, 9, 32/3, 15, hope this helps :)
