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Oduvanchick [21]
2 years ago
13

X2-8x+10=0 solve for x

Mathematics
2 answers:
Pavel [41]2 years ago
8 0

Answer:

\sf x=\sqrt{6} +4

\sf x=4-\sqrt{6}

Step-by-step explanation:

\sf x^2-8x+10=0

Equations of the form ax^2+bx+c=0 can be solved by the quadratic formula:

\boxed{\sf \cfrac{-b\pm \sqrt{b^2-4ac}}{2a}}

Quadratic formula gives you two solutions one when (±) addition and one when (±) is a subtraction:

\sf x^2-8x+10=0

Substitute:

a:1

b:-8

c:10

\sf x=\cfrac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\times \:1\cdot \:10}}{2\times \:1}

Square -8, and multiply -4 by 10:

\sf x=\cfrac{(-8)\pm\sqrt{64-40} }{2}

Add 64 and - 40, and take the square root of 24:

\sf x=\cfrac{-(-8)\pm2\sqrt{6} }{2}

-(-8)= 8

\sf x=\cfrac{8\pm2\sqrt{6} }{2}

Now solve when (±) is a plus and then solve when it is a minus:-

\sf x=\sqrt{6} +4

\sf x=4-\sqrt{6}

____________________________

Oksi-84 [34.3K]2 years ago
3 0

Answer: x = 5/3

Step-by-step explanation:

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