Answer:
y = -3/4x - 6
Step-by-step explanation:
R=$350, I=0.05, n=15
A = 350 (1+0.05)^15 = 350(1.05)^15 = 350 (2.0789)=727.62 <- Answer
Answer:
Probability of missing two passes in a row is 0.08.
Step-by-step explanation:
Event E = A football player misses twice in a row.
P(E) = ?
Event X = Football player misses the first pass
P(X) = 0.4
Event Y = Football player misses just after he first miss
P(Y) = 0.2
Both the events are exclusive so the probability of occuring of these two events can be calculated by the formula:
P(E) = P(X).P(Y)
P(E) = 0.4*0.2
P(E) = 0.08
#1 = 1/3
#2 = 5/6
#3 = 8/9
#4 = 6/7
#5 = 15/20
Answer:
90000
Step-by-step explanation: