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3 years ago

A square tablecloth covers 6 square feet. What is the approximate length of one side of the tablecloth?

Mathematics

2 answers:

sveta [45]3 years ago

7 0

Answer:

Is should be 50 feet for the length of tablecloths

matrenka [14]3 years ago

5 0

3Step-by-step explanation:

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Bob orders 2 tons of dog food every month, the order must be placed in 50 pound sacks. Each sack costs $11.99. How many 50 pound

Aleksandr-060686 [28]

Answer:

80 sacks for $959.2

Step-by-step explanation:

2 tons = 4000 lbs.

If each sack cost $11.99, and is weighted at 50 pounds than

4000/50 = 80

80 x $11.99 = $959.2

4 0

3 years ago

How high is the ramp?

Vinil7 [7]

Answer:

Step-by-step explanation:

it's a right triangle so we can use the pythagorean theorem to find h

pythagorean theorem: a^2+b^2=c^2

h^2+19^2=21^2

h^2+361=441

h^2=80

h≈ 8.9ft

6 0

3 years ago

Read 2 more answers

I need help with this

goblinko [34]

Yes because their both 90° angle triangles

3 0

4 years ago

Read 2 more answers

Evaluate each log without a calculator

Mrac [35]

QUESTION 1

The given logarithmic expression is

$\log_4(\frac{1}{16})$

We rewrite $\frac{1}{16}$ in the index form to base 4.

This implies that;

$\log_4(\frac{1}{16})=\log_4(4^{-2})$

We now apply the power rule: $\log_a(m^n)=n\log_a(m^n)$ .

$\log_4(\frac{1}{16})=-2\log_4(4)$

Recall that logarithm of the base is 1.

$\log_4(\frac{1}{16})=-2(1)$

$\log_4(\frac{1}{16})=-2$

QUESTION 2

The given logarithm is;

$\log_2(\sqrt[5]{32})$

$\log_2(\sqrt[5]{2^5})$

This is the same as;

$\log_2(2^{5\times \frac{1}{5}})$

$\log_2(2^{1})$

$\log_2(2)=1$

6 0

3 years ago

In a certain university admissions department, 70 more males than females submitted applications for admissions. 20% of the fema

Anuta_ua [19.1K]

Answer:

In total, 1130 people applied in the University.

Step-by-step explanation:

Total applicants admitted = 256

Let the number of females who applied in University = k

So, the number of males who applied = ( k + 70)

Now, 20 %of females are admitted ⇒ 20% of (k) is admitted

or, the number of females admitted in university = $\frac{20}{100} \times k = 0.2k$

Also , 25 %of males are admitted ⇒ 25% of (k + 70) is admitted

or, the number of males admitted in university = $\frac{25}{100} \times (k+70) = 0.25(k+70)$

So, according to the question:

0.20k + 0.25(k+70) = Total admissions = 256

or, 0.2k + 0.25k + 17.5 = 256

⇒0.45k = 238.5

or, k = 238.5/0.45 = 530

Hence, total number of females who applied = 530

And Total males who applies = ( k + 70) = 600

Now, TOTAL Applications = MALE applications + FEMALE applications

= 530 + 600 = 1130

Hence, in total 1130 people applied in the University.

4 0

3 years ago