Answer:
f(x) = -2|x| + 1
Step-by-step explanation:
The graph shifts one unit up the y axis since there's a value outside the absolute value which directly adds 1 to it.
8(11 + 2r) = 126r + 3
first open the parenthesis
88 + 16r = 126r + 3
88 - 3 = 126r - 16 r
85 = 110r
divide both-side of the equation by 110
85/110 = r
r= 17/22
he elements of the Klein <span>44</span>-group sitting inside <span><span>A4</span><span>A4</span></span> are precisely the identity, and all elements of <span><span>A4</span><span>A4</span></span>of the form <span><span>(ij)(kℓ)</span><span>(ij)(kℓ)</span></span> (the product of two disjoint transpositions).
Since conjugation in <span><span>Sn</span><span>Sn</span></span> (and therefore in <span><span>An</span><span>An</span></span>) does not change the cycle structure, it follows that this subgroup is a union of conjugacy classes, and therefore is normal.
Answer:
3 and 5
Step-by-step explanation:
Let the two consecutive odd integers be x and x + 2.
Now,
The given statement is
Taking x=3.
Hence, two consecutive odd integers are 3 and 5.
The <span>metric unit of weight.</span>
