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mash [69]
2 years ago
5

HELP ME PLEASE WITH THIS QUESTION! :D

Mathematics
1 answer:
Montano1993 [528]2 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

Using the rule of exponents

a^{m} × a^{n} = a^{(m+n)}

(a)

3 × a × 2 × b

= 3 × 2 × a × b

= 6ab

(b)

c^{5} × c

= c^{(5+1)}

= c^{6}

(c)

2y^{4} × 5y³

= 2 × 5 × y^{4} × y³

= 10 × y^{(4+3)}

=10y^{7}

(d)

3gh² × 4g³h³

= 3 × 4 × g × g³ × h² × h³

= 12 × g^{(1+3)} × h^{(2+3)}

= 12g^{4}h^{5}

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For A I somehow got 41.05 but its 2.95cm can someone show me the working and what I did wrong?
777dan777 [17]

Answer:

Step-by-step explanation:

a). tan(75°) = \frac{\text{Opposite side}}{\text{Adjacent side}}

                  = \frac{11}{k}

    k = \frac{11}{\text{tan}(75)}

    k = 2.947

    k = 2.95 cm

b). cos(52°) = \frac{16}{s}

    s = \frac{16}{\text{cos}(52)}

    s = 25.988

    s ≈ 25.99 cm

c). sin(5°) = \frac{\text{Opposite side}}{\text{Hypotenuse}}

               = \frac{16.1}{q}

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4 0
2 years ago
2 fractions between 3/5 and 4/5
Tasya [4]
Convert the fractions to decimals:

3/5=0.6
4/5=0.8

You have to find 2 fractions between these 2 numbers. You could pick anything.

7/10= 0.7 = less than 0.8 but greater than 0.6

75/100=0.75 = less than 0.8 but greater than 0.6

Hope this helps

3 0
3 years ago
2.57 as a improper fraction
USPshnik [31]

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6 0
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What is the midpoint of the vertical line segment graphed below? (2, 4), (2, -9) A. (4, -5). B. (2, -5/2). C. (2, -5). D. (4, 5/
omeli [17]

Answer:

B. (2, -\frac{5}{2})

Step-by-step explanation:

Given:

(2, 4) and (2, -9)

Required:

Midpoint of the vertical line with the above endpoints

Solution:

Apply the midpoint formula, which is:

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})

Where,

(2, 4) = (x_1, y_1)

(2, -9) = (x_2, y_2)

Plug in the values into the equation:

M(\frac{2 + 2}{2}, \frac{4 + (-9)}{2})

M(\frac{4}{2}, \frac{-5}{2})

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8 0
2 years ago
Ax + b2 = cx + d2<br> ????
ryzh [129]

Answer:

x=b^2+d^2/a-c

Step-by-step explanation:

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